Suppose we want to divide

  4y 3 + 5y 2 + 6y ÷ 2y

 

We first factorise both of them separately

  4y 3 + 5y 2 + 6y = 4 × y 3 + 5 × y 2 + 6 × y

                                     = 2 × 2 × y × y × y + 5 × y × y + 2 × 3 × y

 

2y = 2 × y

Now, Dividing

(4y 3 + 5y 2 + 6y)/2y  = (2 × 2 × y × y × y + 5 × y × y + 2 × 3 × y)/(2 × y)

= (2 × 2 × y × y × y)/(2 × y) + (5 × y × y )/(2 × y) + (2 × 3 × y)/(2 × y)

= 2 × y × y + 5/2 × y + 3

= 2y 2 + 5/2 y + 3

 

 

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo