Suppose we want to divide

  4y 3 + 5y 2 + 6y ÷ 2y

 

We first factorise both of them separately

  4y 3 + 5y 2 + 6y = 4 × y 3 + 5 × y 2 + 6 × y

                                     = 2 × 2 × y × y × y + 5 × y × y + 2 × 3 × y

 

2y = 2 × y

Now, Dividing

(4y 3 + 5y 2 + 6y)/2y  = (2 × 2 × y × y × y + 5 × y × y + 2 × 3 × y)/(2 × y)

= (2 × 2 × y × y × y)/(2 × y) + (5 × y × y )/(2 × y) + (2 × 3 × y)/(2 × y)

= 2 × y × y + 5/2 × y + 3

= 2y 2 + 5/2 y + 3

 

 

  1. Chapter 14 Class 8 Factorisation
  2. Concept wise

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.