Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Example 14 - Chapter 12 Class 8 Factorisation
Last updated at May 29, 2023 by Teachoo
Transcript
Example 14 (Method 1 β Separating each term) Divide 24(π₯^2yz + γπ₯π¦γ^2z + γπ₯π¦π§γ^2) by 8xyz using both the methods. 24 (π₯^2 π¦π§+π₯π¦^2 π§+π₯π¦π§^2 ) = 24 (π₯Γπ₯π¦π§+π¦Γπ₯π¦π§+π§Γπ₯π¦π§) Taking xyz common = 24 π₯π¦π§ (π₯+π¦+π§) Dividing (24 (π₯^2 π¦π§ + π₯π¦^2 π§ + π₯π¦π§^2))/8π₯π¦π§ = (24 π₯π¦π§ (π₯ + π¦ + π§))/8π₯π¦π§ = (24 π₯π¦π§ (π₯ + π¦ + π§))/8π₯π¦π§ = 3 (π + π + π) Example 14 (Method 2 β Canceling term) Divide 24(π₯^2yz + γπ₯π¦γ^2z + γπ₯π¦π§γ^2) by 8xyz using both the methods. (24 (π₯^2 π¦π§ + π₯π¦^2 π§ + π₯π¦π§^2))/8π₯π¦π§ = 24/8 Γ ((π₯^2 π¦π§ + π₯π¦^2 π§ + π₯π¦π§^2))/π₯π¦π§ = 3 Γ ((π₯^2 π¦π§ + π₯π¦^2 π§ + π₯π¦π§^2))/π₯π¦π§ = 3 Γ ((π₯^2 π¦π§ )/π₯π¦π§+(π₯π¦^2 π§)/π₯π¦π§+(π₯π¦π§^2)/π₯π¦π§) = 3 Γ (π₯ + π¦ + π§) = 3 (π + π + π)
