
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Last updated at May 29, 2023 by Teachoo
Ex 12.3, 2 (Method 1) Divide the given polynomial by the given monomial. (ii) (3π¦^8 β 4π¦^6 + 5π¦^4) Γ· π¦^4 3π¦^8 β 4π¦^6 + 5π¦^4 = (3π¦^4Γπ¦^4 ) β (4y^2Γπ¦^4 )+(5Γy^4) Taking π¦^4 common = π¦^4 (3π¦^4 β 4π¦^2+5) Dividing (3π¦^8 β 4π¦^6 + 5π¦^4)/π¦^4 = (π¦^4 (3π¦^4 β γ4π¦γ^4 + 5))/π¦^4 = ππ^π β ππ^π + π Ex 12.3, 2 (Method 2) Divide the given polynomial by the given monomial. (ii) (3π¦^8 β 4π¦^6 + 5π¦^4) Γ· π¦^4 (3π¦^8 β 4π¦^6 + 5π¦^4)/π¦^4 = (3π¦^8)/π¦^4 βγ4π¦γ^6/π¦^4 +(5π¦^4)/π¦^4 = 3Γπ¦^(8 β 4)β 4Γ π¦^(6 β 4)+5Γπ¦^(4 β 4) = 3Γπ¦^4β 4Γ π¦^2+γ5π¦γ^0 = γππγ^π β ππ^π+π (π΄π π^π/π^π =π^(π β n) ) (As π^0=1)