Check sibling questions

Ex 14.3, 2 (ii) - Divide (3y^8 - 4y^6 + 5y^4) Γ· y^4 - Polynomial by

Ex 14.3, 2 (ii) - Chapter 14 Class 8 Factorisation - Part 2

Introducing your new favourite teacher - Teachoo Black, at only β‚Ή83 per month


Transcript

Ex 14.3, 2 (Method 1) Divide the given polynomial by the given monomial. (ii) (3𝑦^8 – 4𝑦^6 + 5𝑦^4) Γ· 𝑦^4 3𝑦^8 – 4𝑦^6 + 5𝑦^4 = (3𝑦^4×𝑦^4 ) βˆ’ (4y^2×𝑦^4 )+(5Γ—y^4) Taking 𝑦^4 common = 𝑦^4 (3𝑦^4 βˆ’ 4𝑦^2+5) Dividing (3𝑦^8 βˆ’ 4𝑦^6 + 5𝑦^4)/𝑦^4 = (𝑦^4 (3𝑦^4 βˆ’ γ€–4𝑦〗^4 + 5))/𝑦^4 = πŸ‘π’š^πŸ’ βˆ’ πŸ’π’š^𝟐 + πŸ“ Ex 14.3, 2 (Method 2) Divide the given polynomial by the given monomial. (ii) (3𝑦^8 – 4𝑦^6 + 5𝑦^4) Γ· 𝑦^4 (3𝑦^8 βˆ’ 4𝑦^6 + 5𝑦^4)/𝑦^4 = (3𝑦^8)/𝑦^4 βˆ’γ€–4𝑦〗^6/𝑦^4 +(5𝑦^4)/𝑦^4 = 3×𝑦^(8 βˆ’ 4)βˆ’ 4Γ— 𝑦^(6 βˆ’ 4)+5×𝑦^(4 βˆ’ 4) = 3×𝑦^4βˆ’ 4Γ— 𝑦^2+γ€–5𝑦〗^0 = γ€–πŸ‘π’šγ€—^πŸ’ βˆ’ πŸ’π’š^𝟐+πŸ“ (𝐴𝑠 π‘Ž^π‘š/π‘Ž^𝑛 =π‘Ž^(π‘š βˆ’ n) ) (As π‘Ž^0=1)

Davneet Singh's photo - Teacher, Engineer, Marketer

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.