
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Last updated at May 29, 2023 by Teachoo
Ex 12.3, 2 (Method 1) Divide the given polynomial by the given monomial. (v) (π^3 π^6 β π^6 π^3) Γ· π^3 π^3 π^3 π^6 β π^6 π^3 = (π^3 π^3 Γ π^3) β (π^3 π^3 Γ π^3) Taking π^3 π^3common, = π^3 π^3(π^3βπ^3) Dividing (π^3 π^6 " " βγ πγ^6 π^3)/(π^3 π^3 ) = (π^3 π^3 (π^3βπ^3))/(π^3 π^3 ) = π^πβπ^π Ex 12.3, 2 (Method 2) Divide the given polynomial by the given monomial. (v) (π^3 π^6 β π^6 π^3) Γ· π^3 π^3 (π^3 π^6 " " βγ πγ^6 π^3)/(π^3 π^3 ) = (π^3 π^6 )/(π^3 π^3 ) β (π^6 π^3)/(π^3 π^3 ) = π^6/π^3 βπ^6/π^3 = π^(6 β 3) β π^(6 β 3) = π^πβπ^π ("As" π^π/π^π =π^(π β n) )