Ex 12.3, 5 (vii) - Chapter 12 Class 8 Factorisation

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Ex 12.3, 5 (vii) - Factorise and divide 39y^3 (50y^2 - 98) ÷ 26y2(5y+7 - Ex 12.3

part 2 - Ex 12.3, 5 (vii) - Ex 12.3 - Serial order wise - Chapter 12 Class 8 Factorisation

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Transcript

Ex 12.3, 5 Factorise the expressions and divide them as directed. (vii) 39๐‘ฆ^3(50๐‘ฆ^2 โ€“ 98) รท 26๐‘ฆ^2 (5y + 7)We first factorise ใ€–39๐‘ฆใ€—^3 (50๐‘ฆ^2โˆ’ 98) = ใ€–39๐‘ฆใ€—^3 (2ร—ใ€–25๐‘ฆใ€—^2 โˆ’ 2 ร— 49) Taking 2 common = ใ€–39๐‘ฆใ€—^3ร—2 (ใ€–25๐‘ฆใ€—^2โˆ’49) = ใ€–78๐‘ฆใ€—^3 (ใ€–25๐‘ฆใ€—^2โˆ’49) = ใ€–๐Ÿ•๐Ÿ–๐’šใ€—^๐Ÿ‘ [(ใ€–๐Ÿ“๐’šใ€—^๐Ÿ)โˆ’(๐Ÿ•)^๐Ÿ] = ใ€–78๐‘ฆใ€—^3 (5y โˆ’ 7) (5y + 7) Dividing 39๐‘ฆ^3(50๐‘ฆ^2 โ€“ 98) รท 26๐‘ฆ^2 (5y + 7) = (39๐‘ฆ^3 (50๐‘ฆ^2 โˆ’ 98))/(26๐‘ฆ^2 (5๐‘ฆ + 7)) = (๐Ÿ•๐Ÿ–๐’š^๐Ÿ‘ (๐Ÿ“๐’š + ๐Ÿ•) (๐Ÿ“๐’š โˆ’ ๐Ÿ•))/(๐Ÿ๐Ÿ”๐’š^๐Ÿ (๐Ÿ“๐’š + ๐Ÿ•)) = 78/26 ร— ๐‘ฆ^3/๐‘ฆ^2 ร— ((5๐‘ฆ + 7))/((5๐‘ฆ + 7)) ร— (5y โˆ’ 7) = 3 ร— y ร— (5y โˆ’7) = 3y (5y โˆ’ 7)

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