Ex 12.3, 5 (iii) - Factorise and divide (5p^2 - 25p + 20) ÷ (p - 1) - Ex 12.3

part 2 - Ex 12.3, 5 (iii) - Ex 12.3 - Serial order wise - Chapter 12 Class 8 Factorisation

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Ex 12.3, 5 Factorise the expressions and divide them as directed. (iii) (5๐‘^2 โ€“ 25p + 20) รท (p โ€“ 1)We first factorise ใ€–๐Ÿ“๐’‘ใ€—^๐Ÿ โˆ’ 25p + 20 Taking 5 common, = 5 (๐‘^2โˆ’5๐‘+4) By middle term splitting, = 5 (๐‘^2โˆ’๐’‘โˆ’๐Ÿ’๐’‘+4) = 5 [(๐‘^2โˆ’ p) โˆ’ (4p โˆ’ 4)] = 5 [p(p โˆ’ 1) โˆ’ 4 (p โˆ’ 1)] Taking (p โˆ’ 1) common, = 5 (p โˆ’ 1)(p โˆ’ 4) Splitting the middle term We need to find two numbers whose Sum = โˆ’5 Product = 4 So, we write โˆ’5p = โˆ’p โˆ’ 4p Dividing (ใ€–5๐‘ใ€—^2โˆ’25๐‘+20)รท(๐‘+1) = (ใ€–5๐‘ใ€—^2 โˆ’ 25๐‘ + 20)/((๐‘ โˆ’1)) = (๐Ÿ“ (๐’‘ โˆ’๐Ÿ) (๐’‘โˆ’๐Ÿ’))/((๐’‘ โˆ’๐Ÿ)) = 5 ร— ((๐‘ โˆ’ 1) )/((๐‘ โˆ’ 1)) ร— (p โˆ’ 4) = 5 (p โˆ’ 4)

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