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Dividing two polynomials
Ex 14.3, 4 (i)
Ex 14.3, 4 (v) Important
Ex 14.3, 4 (iv)
Ex 14.3, 4 (ii) Important
Ex 14.3, 4 (iii)
Ex 14.3, 3 (i)
Ex 14.3, 3 (ii)
Ex 14.3, 3 (iii) Important
Ex 14.3, 3 (iv)
Ex 14.3, 3 (v) Important
Ex 14.3, 5 (i)
Ex 14.3, 5 (ii) Important
Ex 14.3, 5 (iii) You are here
Ex 14.3, 5 (iv) Important
Ex 14.3, 5 (v)
Ex 14.3, 5 (vi)
Ex 14.3, 5 (vii) Important
Example 15 Important
Example 16
Last updated at Dec. 26, 2018 by Teachoo
Ex 14.3, 5 Factorise the expressions and divide them as directed. (iii) (5π^2 β 25p + 20) Γ· (p β 1) We first factorise γ5πγ^2 β 25p + 20 Taking 5 common, = 5 (π^2β5π+4) By middle term splitting, = 5 (π^2βπβ4π+4) = 5 [(π^2β p) β (4p β 4)] = 5 [p(p β 1) β 4 (p β 1)] Taking (p β 1) common, = 5 (p β 1)(p β 4) Splitting the middle term We need to find two numbers whose Sum = β5 Product = 4 So, we write β5p = βp β 4p Dividing (γ5πγ^2β25π+20)Γ·(π+1) = (γ5πγ^2 β 25π + 20)/((π β1)) = (5 (π β1) (πβ4))/((π β1)) = 5 Γ ((π β 1) )/((π β 1)) Γ (p β 4) = 5 (p β 4)