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Dividing two polynomials

Dividing polynomial by polynomial

Ex 12.3, 4 (i)

Ex 12.3, 4 (v) Important

Ex 12.3, 4 (iv)

Ex 12.3, 4 (ii) Important

Ex 12.3, 4 (iii)

Ex 12.3, 3 (i)

Ex 12.3, 3 (ii)

Ex 12.3, 3 (iii) Important

Ex 12.3, 3 (iv) You are here

Ex 12.3, 3 (v) Important

Ex 12.3, 5 (i)

Ex 12.3, 5 (ii) Important

Ex 12.3, 5 (iii)

Ex 12.3, 5 (iv) Important

Ex 12.3, 5 (v)

Ex 12.3, 5 (vi)

Ex 12.3, 5 (vii) Important

Example 15 Important

Example 16

Last updated at May 18, 2023 by Teachoo

Ex 12.3, 3 Work out the following divisions. (iv) 9π₯^2 π¦^2(3z β 24) Γ· 27xy(z β 8) We first factorise γ9π₯γ^2 π¦^2 (3z β 24) = γ9π₯γ^2 π¦^2 Γ [3z β (3 Γ 8)] Taking 3 common, = γ9π₯γ^2 π¦^2 Γ 3 (z β 8) = 27 π₯^2 π¦^2 (z β 8) Dividing, (9π₯^2 π¦^2 (3π§ β 24))/(27π₯π¦ (π§ β 8)) = (27π₯^2 π¦^2 (π§ β 8))/(27π₯π¦ (π§ β 8)) = 27/27 Γ π₯^2/π₯ Γ π¦^2/π¦ Γ ((π§ β 8))/((π§ β 8)) = 1 Γ x Γ y Γ 1 = xy (π΄π π^π/π^π =π^(π β n) )