Ex 12.3, 5 (vi) - Factorise and divide 12xy(9x2 - 16y2) ÷ 4xy(3x+4y) - Ex 12.3

part 2 - Ex 12.3, 5 (vi) - Ex 12.3 - Serial order wise - Chapter 12 Class 8 Factorisation

Remove Ads

Transcript

Ex 12.3, 5 Factorise the expressions and divide them as directed. (vi) 12xy(9๐‘ฅ^2 โ€“ 16๐‘ฆ^2) รท 4xy(3x + 4y)We first factorise 12xy (ใ€–9๐‘ฅใ€—^2โˆ’16๐‘ฆ^2) = 12xy [(ใ€–3๐‘ฅใ€—^2) โˆ’ (ใ€–4๐‘ฆใ€—^2)] Using ๐’‚^๐Ÿ โˆ’ ๐’ƒ^๐Ÿ = (a + b) (a โˆ’ b) Here ๐‘Ž= 3x and b = 4y = 12xy (3x + 4y) (3x โˆ’ 4) Dividing 12xy (ใ€–9๐‘ฅใ€—^2โˆ’16๐‘ฆ^2) รท 4xy (3x + 4y) = (12๐‘ฅ๐‘ฆ (9๐‘ฅ^2 โˆ’ 16๐‘ฆ^2))/(4๐‘ฅ๐‘ฆ (3๐‘ฅ + 4๐‘ฆ)) = (๐Ÿ๐Ÿ๐’™๐’š (๐Ÿ‘๐’™ + ๐Ÿ’๐’š) (๐Ÿ‘๐’™ โˆ’ ๐Ÿ’๐’š))/(๐Ÿ’๐’™๐’š (๐Ÿ‘๐’™ + ๐Ÿ’๐’š)) = 12/4 ร— ๐‘ฅ๐‘ฆ/๐‘ฅ๐‘ฆ ร— ((3๐‘ฅ + 4๐‘ฆ))/((3๐‘ฅ + 4๐‘ฆ)) ร— (3x โˆ’ 4y) = 3 (3x โˆ’ 4y)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.