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Ex 14.3, 5 (vi) - Factorise and divide 12xy(9x2 - 16y2) Γ· 4xy(3x+4y)

Ex 14.3, 5 (vi) - Chapter 14 Class 8 Factorisation - Part 2

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Ex 14.3, 5 Factorise the expressions and divide them as directed. (vi) 12xy(9π‘₯^2 – 16𝑦^2) Γ· 4xy(3x + 4y) We first factorise 12xy (γ€–9π‘₯γ€—^2βˆ’16𝑦^2) = 12xy [(γ€–3π‘₯γ€—^2) βˆ’ (γ€–4𝑦〗^2)] We first factorise 12xy (γ€–9π‘₯γ€—^2βˆ’16𝑦^2) = 12xy [(γ€–3π‘₯γ€—^2) βˆ’ (γ€–4𝑦〗^2)] Using π‘Ž^2 βˆ’ 𝑏^2 = (a + b) (a βˆ’ b) Here π‘Ž= 3x and b = 4y Using π‘Ž^2 βˆ’ 𝑏^2 = (a + b) (a βˆ’ b) Here π‘Ž= 3x and b = 4y = (12π‘₯𝑦 (9π‘₯^2 βˆ’ 16𝑦^2))/(4π‘₯𝑦 (3π‘₯ + 4𝑦)) = (12π‘₯𝑦 (3π‘₯ + 4𝑦) (3π‘₯ βˆ’ 4𝑦))/(4π‘₯𝑦 (3π‘₯ + 4𝑦)) = 12/4 Γ— π‘₯𝑦/π‘₯𝑦 Γ— ((3π‘₯ + 4𝑦))/((3π‘₯ + 4𝑦)) Γ— (3x βˆ’ 4y) = 3 (3x βˆ’ 4y)

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