Definite Integration - By Formulae
Definite Integration - By Formulae
Last updated at August 5, 2026 by Teachoo
Transcript
Ex 7.8, 3 ā«_1^2āć(4š„3ā5š„2+6š„+9) šš„ć Step 1 :- F(š„)=ā«1ā(4š„^3ā5š„^2+6š„+9)šš„ =(4š„^(3+1))/(3+1)ā(5š„^(2+1))/(2+1)+(6š„^(1+1))/(1+1)+9š„ =(4š„^4)/4ā(5š„^3)/3+(6š„^2)/2+9š„ = š„^4ā5/3 š„^3+ć3š„ć^2+9š„ Hence f(x)ć=š„ć^4ā(3š„^3)/3+3š„^2+9š„ Step 2 :- ā«_1^2āć(4š„^2ā9š„^2+6š„+9)šš„ ć =š¹(2)āš¹(1) =(2)^4ā5/3 (2)^3+3(2)^2+9(2)ā(1^4ā5/3 Ć1^3+3 Ć1^2+9 Ć1) =16ā5/3 Ć8+3 Ć4+9 Ć2ā1+5/3ā3ā9 =16ā40/3 +12+18ā1+5/3ā3ā9 =33ā35/3 =(3(33) ā 35)/3 = šš/š