Using Trignometric Formulaes
Last updated at Dec. 11, 2021 by Teachoo
Ex 7.1, 1 Find anti derivative of sin 2x We know that γ (cosβ‘γ π₯γ )γ^β²=γβsinγβ‘π₯ γ (ππ¨π¬β‘γ ππγ )γ^β²=γβπ¬π’π§γβ‘ππ Γ π (β1)/( 2) (cosβ‘γ 2π₯γ )^β²=sinβ‘2π₯ sinβ‘2π₯=(β1)/( 2) (cosβ‘2π₯ )^β² sinβ‘2π₯=((β1)/( 2) cosβ‘2π₯ )^β² β΄ Anti derivate of π ππβ‘2π₯=(βπ)/π ππ¨π¬β‘ππ