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Ex 7.1,1 - Chapter 7 Class 12 Integrals
Last updated at July 21, 2026 by Teachoo
Chapter 7 Class 12 Integrals
Concept wise
- Using Formulaes
-
Using Trignometric Formulaes
- Integration by substitution - x^n
- Integration by substitution - lnx
- Integration by substitution - e^x
- Integration by substitution - Trignometric - Normal
- Integration by substitution - Trignometric - Inverse
- Integration using trigo identities - sin^2,cos^2 etc formulae
- Integration using trigo identities - a-b formulae
- Integration using trigo identities - 2x formulae
- Integration using trigo identities - 3x formulae
- Integration using trigo identities - CD and CD inv formulae
- Integration using trigo identities - Inv Trigo formulae
- Integration by parts
- Integration by parts - e^x integration
- Integration by specific formulaes - Formula 1
- Integration by specific formulaes - Formula 2
- Integration by specific formulaes - Formula 3
- Integration by specific formulaes - Formula 4
- Integration by specific formulaes - Formula 5
- Integration by specific formulaes - Formula 6
- Integration by specific formulaes - Formula 7
- Integration by specific formulaes - Formula 8
- Integration by specific formulaes - Method 9
- Integration by specific formulaes - Method 10
- Integration by partial fraction - Type 1
- Integration by partial fraction - Type 2
- Integration by partial fraction - Type 3
- Integration by partial fraction - Type 4
- Integration by partial fraction - Type 5
- Definite Integral as a limit of a sum
- Definite Integration - By Formulae
- Definite Integration - By Partial Fraction
- Definite Integration - By e formula
- Definite Integration - By Substitution
- Definite Integration by properties - P2
- Definite Integration by properties - P3
- Definite Integration by properties - P4
- Definite Integration by properties - P6
- Definite Integration by properties - P7
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Transcript
Ex 7.1, 1 Find anti derivative of sin 2x We know that γ (cosβ‘γ π₯γ )γ^β²=γβsinγβ‘π₯ γ (ππ¨π¬β‘γ ππγ )γ^β²=γβπ¬π’π§γβ‘ππ Γ π (β1)/( 2) (cosβ‘γ 2π₯γ )^β²=sinβ‘2π₯ sinβ‘2π₯=(β1)/( 2) (cosβ‘2π₯ )^β² sinβ‘2π₯=((β1)/( 2) cosβ‘2π₯ )^β² β΄ Anti derivate of π ππβ‘2π₯=(βπ)/π ππ¨π¬β‘ππ
