
Definite Integration - By Formulae
Definite Integration - By Formulae
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Ex 7.8, 1 β«_(β1)^1β(π₯+1)ππ₯ Let F(π)=β«1β(π₯+1)ππ₯ =π₯^(1+1)/(1+1)+π₯ =π^π/π+π Hence F(π₯)=π₯^2/2+π₯ β«_(βπ)^πβ(π+π)π π =π(π)βπ(βπ) =((1)^2/2+1)β((β1)^2/2+(β1)) =(1/2+1)β(1/2β1) =1/2+1β1/2+1 = 1/2β1/2+1+1 = 2