Chapter 7 Class 12 Integrals
Concept wise

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Transcript

Ex 7.8, 17 ∫_0^(πœ‹/4)β–’(2 sec^2⁑π‘₯+π‘₯^3+2) 𝑑π‘₯ Let F(π‘₯)=∫1β–’γ€–(2 sec^2⁑〖π‘₯+π‘₯^3+2γ€— ) 𝑑π‘₯γ€— =2∫1β–’γ€–sec^2⁑〖π‘₯ 𝑑π‘₯γ€—+∫1β–’γ€–π‘₯^3 𝑑π‘₯+∫1β–’γ€–2 𝑑π‘₯γ€—γ€—γ€— =2 tan⁑〖π‘₯+π‘₯^4/4+2π‘₯γ€— Hence F(π‘₯)=2 tan⁑〖π‘₯+π‘₯^4/4+2π‘₯γ€— Now, ∫_0^(πœ‹/4)β–’γ€–(2𝑠𝑒𝑐^2 π‘₯+π‘₯^3+2)𝑑π‘₯=𝐹(πœ‹/4)βˆ’πΉ(0) γ€— =[2π‘‘π‘Žπ‘› πœ‹/4+(πœ‹/4)^4/4+2 πœ‹/4]βˆ’[2π‘‘π‘Žπ‘›(0)+(0)^4/4+2 Γ—0] =2π‘‘π‘Žπ‘› πœ‹/4+πœ‹^4/4^4 Γ— 1/4+πœ‹/2βˆ’[2Γ—0+0+0] =2 Γ—1+πœ‹^4/4^5 +πœ‹/2βˆ’0 =𝟐+𝝅^πŸ’/πŸπŸŽπŸπŸ’+𝝅/𝟐

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.