Chapter 7 Class 12 Integrals
Concept wise

Ex 7.10, 1 - Using properties of definite integrals - Chapter 7 - Ex 7.10

part 2 - Ex 7.10, 1 - Ex 7.10 - Serial order wise - Chapter 7 Class 12 Integrals
part 3 - Ex 7.10, 1 - Ex 7.10 - Serial order wise - Chapter 7 Class 12 Integrals part 4 - Ex 7.10, 1 - Ex 7.10 - Serial order wise - Chapter 7 Class 12 Integrals

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Ex 7.10, 1 By using the properties of definite integrals, evaluate the integrals : ∫_0^(πœ‹/2)β–’γ€–cos^2⁑π‘₯ 𝑑π‘₯γ€— Let 𝐈=∫_𝟎^(𝝅/𝟐)▒〖〖𝒄𝒐𝒔〗^πŸβ‘π’™ 𝒅𝒙〗 I=∫_𝟎^(𝝅/𝟐)β–’γ€–γ€–πœπ¨π¬γ€—^𝟐⁑ (𝝅/πŸβˆ’π’™)𝒅𝒙〗 I= ∫_𝟎^((𝝅 )/𝟐)▒〖〖𝐬𝐒𝐧〗^𝟐 𝒙〗⁑𝒅𝒙 Adding (1) and (2) I+I= ∫_0^(πœ‹/2)β–’γ€–cos^2⁑π‘₯ 𝑑π‘₯γ€— + ∫_0^((πœ‹ )/2)β–’γ€–sin^2 π‘₯〗⁑𝑑π‘₯ 2I= ∫_0^((πœ‹ )/2)β–’(cos^2⁑〖π‘₯+sin^2⁑π‘₯ γ€— )⁑𝑑π‘₯ 𝟐𝐈 =∫_𝟎^((𝝅 )/𝟐)β–’γ€–πŸ .〗⁑𝒅𝒙 2I=[π‘₯]_0^(πœ‹/2) 2I =πœ‹/2βˆ’0 2I =πœ‹/2 𝐈=𝝅/πŸ’ Evaluate: ∫_0^πœ‹β–’γ€–π‘’^cos⁑π‘₯ /(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— Let I=∫_0^πœ‹β–’γ€–π‘’^cos⁑π‘₯ /(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— " " I= ∫_0^πœ‹β–’γ€–π‘’^cos⁑〖(πœ‹ βˆ’ π‘₯)γ€— /(𝑒^cos⁑〖(πœ‹ βˆ’ π‘₯)γ€— + 𝑒^γ€–βˆ’cos〗⁑〖(πœ‹ βˆ’ π‘₯)γ€— ) 𝑑π‘₯γ€— " " I=∫_0^πœ‹β–’γ€–π‘’^γ€–βˆ’cos〗⁑π‘₯ /(𝑒^γ€–βˆ’cos〗⁑π‘₯ + 𝑒^(γ€–βˆ’(βˆ’cos〗⁑π‘₯)) ) 𝑑π‘₯γ€— I=∫_0^πœ‹β–’γ€–π‘’^γ€–βˆ’cos〗⁑π‘₯ /(𝑒^γ€–βˆ’cos〗⁑π‘₯ + 𝑒^cos⁑π‘₯ ) 𝑑π‘₯γ€— Evaluate: ∫_0^πœ‹β–’γ€–π‘’^cos⁑π‘₯ /(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— Let I=∫_0^πœ‹β–’γ€–π‘’^cos⁑π‘₯ /(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— " " I= ∫_0^πœ‹β–’γ€–π‘’^cos⁑〖(πœ‹ βˆ’ π‘₯)γ€— /(𝑒^cos⁑〖(πœ‹ βˆ’ π‘₯)γ€— + 𝑒^γ€–βˆ’cos〗⁑〖(πœ‹ βˆ’ π‘₯)γ€— ) 𝑑π‘₯γ€— " " I=∫_0^πœ‹β–’γ€–π‘’^γ€–βˆ’cos〗⁑π‘₯ /(𝑒^γ€–βˆ’cos〗⁑π‘₯ + 𝑒^(γ€–βˆ’(βˆ’cos〗⁑π‘₯)) ) 𝑑π‘₯γ€— I=∫_0^πœ‹β–’γ€–π‘’^γ€–βˆ’cos〗⁑π‘₯ /(𝑒^γ€–βˆ’cos〗⁑π‘₯ + 𝑒^cos⁑π‘₯ ) 𝑑π‘₯γ€— Adding (1) and (2) i.e. (1) + (2) I+I=∫_0^πœ‹β–’γ€–π‘’^cos⁑π‘₯ /(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— + ∫_0^πœ‹β–’γ€–π‘’^γ€–βˆ’cos〗⁑π‘₯ /(𝑒^γ€–βˆ’cos〗⁑π‘₯ + 𝑒^cos⁑π‘₯ ) 𝑑π‘₯γ€— 2I=∫_0^πœ‹β–’γ€–(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ )/(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— 2I =∫_0^πœ‹β–’γ€–1 .〗⁑𝑑π‘₯ 2I=[π‘₯]_0^πœ‹ 2I =πœ‹βˆ’0 2I =πœ‹ 𝐈=𝝅/𝟐

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