# Example 8 (i) - Chapter 7 Class 12 Integrals

Last updated at Sept. 25, 2018 by Teachoo

Last updated at Sept. 25, 2018 by Teachoo

Transcript

Example 8 (i) Find the following integrals: (i) β« ππ₯/(π₯^2 β 16) β«1βππ₯/(π₯^2 β16) = β«1βππ₯/(π₯^2 βγ 4γ^2 ) Using β«1βγππ₯/(π₯^2 β π^2 )=1/2π πππ|(π₯ β π)/(π₯ + π)|+πΆγ Replacing π=4 =1/(2 Γ 4) πππ|(π₯ β 4)/(π₯ + 4)|+πΆ =π/π πππ|(π β π)/(π + π)|+πͺ

Integration by specific formulaes - Formula 1

Chapter 7 Class 12 Integrals

Concept wise

- Using Formulaes
- Using Trignometric Formulaes
- Integration by substitution - x^n
- Integration by substitution - lnx
- Integration by substitution - e^x
- Integration by substitution - Trignometric - Normal
- Integration by substitution - Trignometric - Inverse
- Integration using trigo identities - sin^2,cos^2 etc formulae
- Integration using trigo identities - a-b formulae
- Integration using trigo identities - 2x formulae
- Integration using trigo identities - 3x formulae
- Integration using trigo identities - CD and CD inv formulae
- Integration using trigo identities - Inv Trigo formulae
- Integration by parts
- Integration by parts - e^x integration
- Integration by specific formulaes - Formula 1
- Integration by specific formulaes - Formula 2
- Integration by specific formulaes - Formula 3
- Integration by specific formulaes - Formula 4
- Integration by specific formulaes - Formula 5
- Integration by specific formulaes - Formula 6
- Integration by specific formulaes - Formula 7
- Integration by specific formulaes - Formula 8
- Integration by specific formulaes - Method 9
- Integration by specific formulaes - Method 10
- Integration by partial fraction - Type 1
- Integration by partial fraction - Type 2
- Integration by partial fraction - Type 3
- Integration by partial fraction - Type 4
- Integration by partial fraction - Type 5
- Definate Integral as a limit of a sum
- Definate Integration - By Formulae
- Definate Integration - By Partial Fraction
- Definate Integration - By e formula
- Definate Integration - By Substitution
- Definate Integration by properties - P2
- Definate Integration by properties - P3
- Definate Integration by properties - P4
- Definate Integration by properties - P6
- Definate Integration by properties - P7

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.