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Ex 7.4, 6 - Chapter 7 Class 12 Integrals
Last updated at August 5, 2026 by Teachoo
Integration by specific formulaes - Formula 2
Chapter 7 Class 12 Integrals
Concept wise
- Using Formulaes
- Using Trignometric Formulaes
- Integration by substitution - x^n
- Integration by substitution - lnx
- Integration by substitution - e^x
- Integration by substitution - Trignometric - Normal
- Integration by substitution - Trignometric - Inverse
- Integration using trigo identities - sin^2,cos^2 etc formulae
- Integration using trigo identities - a-b formulae
- Integration using trigo identities - 2x formulae
- Integration using trigo identities - 3x formulae
- Integration using trigo identities - CD and CD inv formulae
- Integration using trigo identities - Inv Trigo formulae
- Integration by parts
- Integration by parts - e^x integration
- Integration by specific formulaes - Formula 1
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Integration by specific formulaes - Formula 2
- Integration by specific formulaes - Formula 3
- Integration by specific formulaes - Formula 4
- Integration by specific formulaes - Formula 5
- Integration by specific formulaes - Formula 6
- Integration by specific formulaes - Formula 7
- Integration by specific formulaes - Formula 8
- Integration by specific formulaes - Method 9
- Integration by specific formulaes - Method 10
- Integration by partial fraction - Type 1
- Integration by partial fraction - Type 2
- Integration by partial fraction - Type 3
- Integration by partial fraction - Type 4
- Integration by partial fraction - Type 5
- Definite Integral as a limit of a sum
- Definite Integration - By Formulae
- Definite Integration - By Partial Fraction
- Definite Integration - By e formula
- Definite Integration - By Substitution
- Definite Integration by properties - P2
- Definite Integration by properties - P3
- Definite Integration by properties - P4
- Definite Integration by properties - P6
- Definite Integration by properties - P7
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Transcript
Ex 7.4, 6 2/(1 6) Let ^3= Diff both sides w.r.t. x 3 ^2= / = /(3 ^2 ) Integrating the function . . . 1 ^2/(1 ^6 ) = 1 ^2/(1 ( ^3 )^2 ) Put the values of ^3= and = /(3 ^2 ) = 1 ^2/(1 ^2 ) . = 1 ^2/(1 ^2 ) /(3 ^2 ) =1/3 1 /(1 ^2 ) =1/3 1 /((1)^2 ^2 ) =1/3 [1/2(1) log |(1 + )/(1 )| ]+ =1/6 log |(1 + )/(1 )|+ = / |( + ^ )/( ^ )|+
