Ex 7.2, 23 sin^(−1)⁡𝑥/√(1 − 𝑥^2 ) Step 1: Let sin^(−1)⁡𝑥=𝑡 Differentiating both sides 𝑤.𝑟.𝑡.𝑥 1/√(1 − 𝑥^2 )= 𝑑𝑡/𝑑𝑥 𝑑𝑥=√(1 − 𝑥^2 ) .𝑑𝑡 Step 2: Integrating the function ∫1▒〖" " sin^(−1)⁡𝑥/√(1 − 𝑥^2 ) " " 〗. 𝑑𝑥 putting sin^(−1)⁡𝑥=𝑡 & 𝑑𝑥=√(1 − 𝑥^2 ) .𝑑𝑡 = ∫1▒〖𝑡/√(1 − 𝑥^2 ) " " 〗. √(1 − 𝑥^2 ) .𝑑𝑡 = ∫1▒〖𝑡 . 𝑑𝑡〗 = 𝑡^2/2+𝐶 = (〖𝒔𝒊𝒏〗^(−𝟏)⁡𝒙 )^𝟐/𝟐+𝑪

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.

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