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Integration by substitution - Trignometric - Inverse
Integration by substitution - Trignometric - Inverse
Last updated at May 29, 2023 by Teachoo
Ex 7.2, 23 sin^(โ1)โก๐ฅ/โ(1 โ ๐ฅ^2 ) Step 1: Let sin^(โ1)โก๐ฅ=๐ก Differentiating both sides ๐ค.๐.๐ก.๐ฅ 1/โ(1 โ ๐ฅ^2 )= ๐๐ก/๐๐ฅ ๐๐ฅ=โ(1 โ ๐ฅ^2 ) .๐๐ก Step 2: Integrating the function โซ1โใ" " sin^(โ1)โก๐ฅ/โ(1 โ ๐ฅ^2 ) " " ใ. ๐๐ฅ putting sin^(โ1)โก๐ฅ=๐ก & ๐๐ฅ=โ(1 โ ๐ฅ^2 ) .๐๐ก = โซ1โใ๐ก/โ(1 โ ๐ฅ^2 ) " " ใ. โ(1 โ ๐ฅ^2 ) .๐๐ก = โซ1โใ๐ก . ๐๐กใ = ๐ก^2/2+๐ถ = (ใ๐๐๐ใ^(โ๐)โก๐ )^๐/๐+๐ช