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Using Trignometric Formulaes
Last updated at Dec. 20, 2019 by Teachoo
Ex 7.1, 2 Find anti derivative of cosβ‘3π₯ We know that γ (sinβ‘3π₯ )γ^β²=3 cosβ‘3π₯ 1/3 (sinβ‘3π₯ )^β²=cosβ‘3π₯ cosβ‘3π₯=1/3 (sinβ‘3π₯ )^β² cosβ‘3π₯=(1/3 sinβ‘3π₯ )^β² β΄ Antiderivate of πππ β‘3π₯=π/π πππβ‘ππ