Chapter 7 Class 12 Integrals
Concept wise

Ex 7.10, 1 - Using properties of definite integrals - Chapter 7 - Ex 7.10

part 2 - Ex 7.10, 1 - Ex 7.10 - Serial order wise - Chapter 7 Class 12 Integrals
part 3 - Ex 7.10, 1 - Ex 7.10 - Serial order wise - Chapter 7 Class 12 Integrals
part 4 - Ex 7.10, 1 - Ex 7.10 - Serial order wise - Chapter 7 Class 12 Integrals

Share on WhatsApp

Transcript

Ex 7.10, 1 By using the properties of definite integrals, evaluate the integrals : ∫_0^(πœ‹/2)β–’γ€–cos^2⁑π‘₯ 𝑑π‘₯γ€— Let 𝐈=∫_𝟎^(𝝅/𝟐)▒〖〖𝒄𝒐𝒔〗^πŸβ‘π’™ 𝒅𝒙〗 I=∫_𝟎^(𝝅/𝟐)β–’γ€–γ€–πœπ¨π¬γ€—^𝟐⁑ (𝝅/πŸβˆ’π’™)𝒅𝒙〗 I= ∫_𝟎^((𝝅 )/𝟐)▒〖〖𝐬𝐒𝐧〗^𝟐 𝒙〗⁑𝒅𝒙 Adding (1) and (2) I+I= ∫_0^(πœ‹/2)β–’γ€–cos^2⁑π‘₯ 𝑑π‘₯γ€— + ∫_0^((πœ‹ )/2)β–’γ€–sin^2 π‘₯〗⁑𝑑π‘₯ 2I= ∫_0^((πœ‹ )/2)β–’(cos^2⁑〖π‘₯+sin^2⁑π‘₯ γ€— )⁑𝑑π‘₯ 𝟐𝐈 =∫_𝟎^((𝝅 )/𝟐)β–’γ€–πŸ .〗⁑𝒅𝒙 2I=[π‘₯]_0^(πœ‹/2) 2I =πœ‹/2βˆ’0 2I =πœ‹/2 𝐈=𝝅/πŸ’ Evaluate: ∫_0^πœ‹β–’γ€–π‘’^cos⁑π‘₯ /(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— Let I=∫_0^πœ‹β–’γ€–π‘’^cos⁑π‘₯ /(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— " " I= ∫_0^πœ‹β–’γ€–π‘’^cos⁑〖(πœ‹ βˆ’ π‘₯)γ€— /(𝑒^cos⁑〖(πœ‹ βˆ’ π‘₯)γ€— + 𝑒^γ€–βˆ’cos〗⁑〖(πœ‹ βˆ’ π‘₯)γ€— ) 𝑑π‘₯γ€— " " I=∫_0^πœ‹β–’γ€–π‘’^γ€–βˆ’cos〗⁑π‘₯ /(𝑒^γ€–βˆ’cos〗⁑π‘₯ + 𝑒^(γ€–βˆ’(βˆ’cos〗⁑π‘₯)) ) 𝑑π‘₯γ€— I=∫_0^πœ‹β–’γ€–π‘’^γ€–βˆ’cos〗⁑π‘₯ /(𝑒^γ€–βˆ’cos〗⁑π‘₯ + 𝑒^cos⁑π‘₯ ) 𝑑π‘₯γ€— Evaluate: ∫_0^πœ‹β–’γ€–π‘’^cos⁑π‘₯ /(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— Let I=∫_0^πœ‹β–’γ€–π‘’^cos⁑π‘₯ /(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— " " I= ∫_0^πœ‹β–’γ€–π‘’^cos⁑〖(πœ‹ βˆ’ π‘₯)γ€— /(𝑒^cos⁑〖(πœ‹ βˆ’ π‘₯)γ€— + 𝑒^γ€–βˆ’cos〗⁑〖(πœ‹ βˆ’ π‘₯)γ€— ) 𝑑π‘₯γ€— " " I=∫_0^πœ‹β–’γ€–π‘’^γ€–βˆ’cos〗⁑π‘₯ /(𝑒^γ€–βˆ’cos〗⁑π‘₯ + 𝑒^(γ€–βˆ’(βˆ’cos〗⁑π‘₯)) ) 𝑑π‘₯γ€— I=∫_0^πœ‹β–’γ€–π‘’^γ€–βˆ’cos〗⁑π‘₯ /(𝑒^γ€–βˆ’cos〗⁑π‘₯ + 𝑒^cos⁑π‘₯ ) 𝑑π‘₯γ€— Adding (1) and (2) i.e. (1) + (2) I+I=∫_0^πœ‹β–’γ€–π‘’^cos⁑π‘₯ /(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— + ∫_0^πœ‹β–’γ€–π‘’^γ€–βˆ’cos〗⁑π‘₯ /(𝑒^γ€–βˆ’cos〗⁑π‘₯ + 𝑒^cos⁑π‘₯ ) 𝑑π‘₯γ€— 2I=∫_0^πœ‹β–’γ€–(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ )/(𝑒^cos⁑π‘₯ + 𝑒^γ€–βˆ’cos〗⁑π‘₯ ) 𝑑π‘₯γ€— 2I =∫_0^πœ‹β–’γ€–1 .〗⁑𝑑π‘₯ 2I=[π‘₯]_0^πœ‹ 2I =πœ‹βˆ’0 2I =πœ‹ 𝐈=𝝅/𝟐

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo