Minima/ maxima (statement questions) - Geometry questions
Ex 6.3, 27 (MCQ)
Example 23 Important
Example 29 Important
Example 24
Misc 9 Important
Example 25 Important
Misc 6 Important
Ex 6.3,21
Ex 6.3, 20 Important
Ex 6.3,24 Important
Ex 6.3,25 Important
Ex 6.3, 26 Important
Ex 6.3,22 Important
Misc 7
Misc 8 Important
Ex 6.3,17
Ex 6.3,18 Important
Example 36 Important
Ex 6.3,19 Important
Misc 5 Important
Ex 6.3,23 Important
Misc 12 Important
Misc 14 Important
Example 26 Important
Misc 15 Important
Minima/ maxima (statement questions) - Geometry questions
Last updated at April 16, 2024 by Teachoo
Example 30 A car starts from a point P at time t = 0 seconds and stops at point Q. The distance x, in metres, covered by it, in t seconds is given by 𝑥=𝑡^2 (2−𝑡/3). Find the time taken by it to reach Q and also find distance b/w P & Q Given Distance 𝑥 = t2 (2−𝑡/3) At points P and Q, the Velocity of the car is 0 Let 𝑣 be the velocity of the car 𝑣 = Change in Distance w.r.t ttime 𝒗 = 𝒅𝒙/𝒅𝒕 Finding 𝒗 𝑣 = 𝑑(𝑡^2 (2 − 𝑡/3))/𝑑𝑡 𝑣 = 𝑑(2𝑡^2− 𝑡^3/3)/𝑑𝑡 𝑣 = 4t – t2 Putting 𝒗 = 0 4t – t2 = 0 t(4−𝑡)=0 So, t = 0 & t = 4 Thus, it takes 4 seconds to reach from point P to Q Also, Distance PQ = Distance travelled in 4 seconds Finding x at t = 4 𝑥 = t2 (2−𝑡/3) 𝑥 = (4)^2 (2−4/3) = 16 ((6 − 4)/3) = 16 (2/3) = 32/3 𝑚. Hence, Distance PQ = 𝟑𝟐/𝟑 𝒎.