Ex 6.3, 5 (i) - For f(x) = x^3, x โˆˆ [-2, 2], find absolute maximum and - Ex 6.3

part 2 - Ex 6.3, 5 (i) - Ex 6.3 - Serial order wise - Chapter 6 Class 12 Application of Derivatives

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Ex 6.3, 5 Find the absolute maximum value and the absolute minimum value of the following functions in the given intervals: (i) f (๐‘ฅ) = ๐‘ฅ3, ๐‘ฅโˆˆ[โ€“ 2, 2]Finding fโ€™(๐’™) fโ€™(๐‘ฅ)=๐‘‘(๐‘ฅ^3 )/๐‘‘๐‘ฅ fโ€™(๐‘ฅ)=3๐‘ฅ^2 Putting fโ€™(๐’™)=๐ŸŽ 3๐‘ฅ^2=0 ๐‘ฅ^2=0 ๐‘ฅ=0 So, ๐‘ฅ=0 is critical point Since given interval is ๐‘ฅ โˆˆ [โˆ’2 , 2] Hence calculating f(๐‘ฅ) at ๐‘ฅ=โˆ’2 , 0 , 2 Absolute Maximum value of f(x) is 8 at ๐’™ = 2 & Absolute Minimum value of f(x) is โ€“8 at ๐’™ = โ€“2

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