Ex 6.2, 19 - The interval in which y = x2 e-x is increasing

Ex 6.2,19 - Chapter 6 Class 12 Application of Derivatives - Part 2
Ex 6.2,19 - Chapter 6 Class 12 Application of Derivatives - Part 3

Take a fresh quiz. Then take another.
Every attempt is a new AI-adaptive Teachoo quiz with 2 questions, selected from your answers, mistakes, and progress.
Remove Ads

Transcript

Ex 6.2, 19 The interval in which 𝑦 = π‘₯2 𝑒^(–π‘₯) is increasing is (A) (– ∞, ∞) (B) (– 2, 0) (C) (2, ∞) (D) (0, 2)Let f(π‘₯) = π‘₯^2 𝑒^(βˆ’π‘₯) Finding f’(𝒙) f’(π‘₯) = (π‘₯^2 𝑒^(βˆ’π‘₯) )β€² Using product rule f’(π‘₯) = (π‘₯2)β€² 𝑒^(βˆ’π‘₯) + (𝑒^(βˆ’π‘₯) )’ (π‘₯2) f’(π‘₯) = (2π‘₯) 𝑒^(βˆ’π‘₯) + (γ€–βˆ’π‘’γ€—^(βˆ’π‘₯) ) (π‘₯2) f’(π‘₯) = 2π‘₯ 𝑒^(βˆ’π‘₯)βˆ’π‘’^(βˆ’π‘₯) π‘₯2 f’(𝒙) = 𝒙 e –𝒙 (πŸβˆ’π’™) Putting f’(𝒙)=𝟎 𝒙 e –𝒙 (πŸβˆ’π’™)=𝟎 π‘₯ (2βˆ’π‘₯) = 0 So, π‘₯=0 & π‘₯ = 2 Plotting points on real line (As e –π‘₯ is always positive for all π‘₯ ∈ R) Hence, f(π‘₯) is strictly increasing on (0 , 2) Therefore, correct answer is (𝐃)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.