Question 8 - Finding approximate value of numbers - Chapter 6 Class 12 Application of Derivatives

Last updated at August 7, 2026 by

Example 21 - Use differential to approximate root 36.6 - Examples

Example 21 - Chapter 6 Class 12 Application of Derivatives - Part 2

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Question 8 Use differential to approximate āˆš36.6Let y = āˆšš‘„ where x = 36 & ā–³ x = 0.6 Since y = āˆšš’™ š‘‘š‘¦/š‘‘š‘„ = (š‘‘(āˆšš‘„))/š‘‘š‘„ = 1/(2āˆšš‘„) Now, āˆ†š‘¦ = š‘‘š‘¦/š‘‘š‘„ ā–³x = 1/(2āˆšš‘„) (0.6) = 0.6/(2 Ɨ āˆš36) = 0.6/(2 Ɨ 6) = 0.05 Now, āˆš36.6=š‘¦+āˆ†š‘¦ Putting values āˆš36.6=āˆš36+0.05 āˆš36.6=6+0.05 āˆš(šŸ‘šŸ”.šŸ”) = 6.05 Hence, approximate value of āˆš36.6 is 6.05

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