Ex 6.3,6 - Chapter 6 Class 12 Application of Derivatives
Last updated at April 16, 2024 by Teachoo
Local maxima and minima
Last updated at April 16, 2024 by Teachoo
Ex 6.3, 6 Find the maximum profit that a company can make, if the profit function is given by š(š„) = 41 ā 72š„ ā 18š„2The profit function is given by p(x) = 41 ā 72x ā 18x2 pā(x) = ā72 ā 36 x Putting pā (x) = 0 ā72 ā 36x = 0 ā36x = 72 š„ =(ā72)/36= ā2 Now, Pā(x) = ā36 Since Pā (x) < 0 š„=ā2 is the maxima ā“ Maximum profit = p(ā2) p(x) = 41 ā 72x ā 18x2 š(ā2)=41ā72 (ā2)ā18 (ā2)^2 =41+144ā18 (4) =41+144ā72 =113 Hence, the maximum profit is 113 unit.