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  1. Chapter 6 Class 12 Application of Derivatives
  2. Concept wise

Transcript

Example 23 Find the approximate value of f (3.02), where f (x) = 3x2 + 5x + 3.Let x = 3 and โˆ†๐‘ฅ=0.02 Given f(x) = 3x2 + 5x + 3 fโ€™(x) = 6x + 5 Now, โ–ณy = fโ€™(x) โˆ†๐‘ฅ = (6x + 5) 0.02 Also, โˆ†๐‘ฆ = f(x + โˆ†๐‘ฅ) โˆ’ f(x) f (x + โˆ†๐‘ฅ) = f(x) + โˆ†๐‘ฆ f (3.02) = (3x2 + 5x + 3) + (6x + 5) 0.02 Putting x = 3 f (3.02) = [3(3)^2+5(3)+3]+[6(3)+5]0.02 = (27 + 15 + 3) + (23) 0.02 = 45 + 0.46 = 45.46 Hence, approximate value of f (3.02) is 45.46

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.