Finding approximate value of function
Last updated at April 16, 2024 by Teachoo
Question 10 Find the approximate value of f (3.02), where f (x) = 3x2 + 5x + 3.Given f(x) = 3x2 + 5x + 3 where x = 3 and âđĽ=0.02 Finding fâ(x) fâ(x) = 6x + 5 Now, âły = fâ(x) âđ = (6x + 5) 0.02 Putting x = 3 = (6 Ă 3 + 5) 0.02 = 23 Ă 0.02 = 0.46 Now, f(x + âđ) = f(x) + âđ f(3.02) = f(3) + 0.46 = (3 Ă 32 + 5 Ă 3 + 3) + 0.46 = (27 + 15 + 3) + 0.46 = 45 + 0.46 = 45.46 Hence, approximate value of f(3.02) is 45.46