Question 1 - Finding slope of tangent/normal - Chapter 6 Class 12 Application of Derivatives

Last updated at August 13, 2026 by

Example 14 - Find slope of tangent to y = x3 - x at x = 2

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Question 1 Find the slope of the tangent to the curve ๐‘ฆ = ๐‘ฅ3 โ€“ ๐‘ฅ at ๐‘ฅ = 2.We know that Slope of tangent = ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ =๐‘‘(๐‘ฅ^3โˆ’ ๐‘ฅ)/๐‘‘๐‘ฅ =3๐‘ฅ^2โˆ’1 Putting ๐‘ฅ = 2 โ”œ ๐‘‘๐‘ฆ/๐‘‘๐‘ฅโ”ค|_(๐‘ฅ=2)=3(2)^2โˆ’1" " =3(4)โˆ’1=12โˆ’1=11 Thus, slope of the tangent is 11

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