Ex 6.2, 3 Find the intervals in which the function f given by f (𝑥) = sin 𝑥 is (a) strictly increasing in (0 , 𝜋/2) f(𝑥) = sin 𝑥
f’(𝒙) = cos 𝒙
Since
cos 𝑥 > 0 for 𝑥 ∈ ("0 , " 𝜋/2)
∴ f’(𝑥) < 0 for 𝑥 ∈ (0 , π)
Thus, f is strictly increasing in ("0 , " 𝜋/2)
Rough
cos 0 = 1
cos 𝜋/4 = 1/√2
cos 𝜋/2 = 0
Value of cos𝑥 > 0 for (0 , 𝜋/2)
Ex 6.2, 3 Find the intervals in which the function f given by f (𝑥) = Sin x is (b) strictly decreasing (𝜋/2,𝜋)f(𝑥) = sin 𝑥
f’(𝒙) = cos 𝒙
Since
cos 𝑥 < 0 for 𝑥 ∈ (𝜋/2 , 𝜋)
∴ f’(𝑥) < 0 for 𝑥 ∈ (𝜋/2 " , π" )
Thus, f is strictly decreasing in (𝜋/2 " π" )
Rough
cos 𝜋/2 = 0
cos 3𝜋/4 = co𝑠 ("π − " 𝜋/4)
= – cos𝜋/4
= (−1 )/√2
Value of cos 𝑥 < o for 𝑥 ∈ (𝜋/2 , 𝜋)
Ex 6.2, 3 Find the intervals in which the function f given by f (𝑥) = sin x is (c) neither increasing nor decreasing in (0, π)(0 , π) = (0 , 𝜋/2) ∪ (𝜋/2,𝜋)
From 1st part
f(𝑥) is strictly increasing in (0 , 𝜋/2)
And from 2nd part
f(𝑥) is strictly decreasing in (𝜋/2,𝜋)
Thus, f(𝒙) is neither increasing nor decreasing in (0, π)
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo
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