You are here
Ex 6.3,11 - Chapter 6 Class 12 Application of Derivatives
Last updated at August 2, 2026 by Teachoo
Chapter 6 Class 12 Application of Derivatives
Concept wise
- Finding rate of change
- To show increasing/decreasing in whole domain
- To show increasing/decreasing in intervals
- Find intervals of increasing/decreasing
- Finding slope of tangent/normal
- Finding point when tangent is parallel/ perpendicular
- Finding equation of tangent/normal when point and curve is given
- Finding equation of tangent/normal when slope and curve are given
- Finding approximate value of numbers
- Finding approximate value of function
- Finding approximate value- Statement questions
- Finding minimum and maximum values from graph
- Local maxima and minima
- Minima/ maxima (statement questions) - Number questions
- Minima/ maxima (statement questions) - Geometry questions
-
Absolute minima/maxima
Take a fresh quiz. Then take another.
Every attempt is a new AI-adaptive Teachoo quiz with 2 questions, selected from your answers, mistakes, and progress.
Transcript
Ex 6.3, 11 It is given that at š„ = 1, the function š„4 ā 62š„2 + šš„+ 9 attains its maximum value, on the interval [0, 2]. Find the value of a.We have f(š„)=š„4 ā 62š„2 + šš„+ 9 Finding fā(š) fā(š„)=š(š„^4ā 62š„^2 + šš„ + 9)/šš„ = ć4š„ć^3ā62 Ć2š„+š = ć4š„ć^3ā124š„+š Given that at š„=1, f(š„)=š„^4ā62š„^2+šš„+9 attain its Maximum Value i.e. f(š„) maximum at š„=1 ā“ šā(š„)=0 at š„=1 Now, fā(1)=0 ć4š„ć^3ā124š„+š = 0 4(1)^3ā124(1)+a=0 4 ā 124 + a = 0 ā120 + a = 0 a = 120 Hence, a = 120
