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Ex 10.2, 20 - By using concept of equation of a line - Ex 10.2

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  1. Chapter 10 Class 11 Straight Lines
  2. Serial order wise
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Ex 10.2, 20 By using the concept of equation of a line, prove that the three points (3, 0), (–2, –2) and (8, 2) are collinear. We need to prove that the three point (3, 0), (–2, –2), and (8, 2) are collinear i.e. these three points lie on the same line We check if (8, 2) lies on the line made by the points (3, 0) & (–2, –2) We know that equation of line passing through (x1, y1) & (x2, y2) (y – y1) = 𝑦2 − 𝑦1﷮𝑥2 − 𝑥1﷯(x – x1) Equation of line passing though (3, 0) & ( − 2, 2) (y – 0) = ( − 2 − 0)﷮( − 2 − 3)﷯ (x – 3) y = − 2﷮ − 5﷯ (x – 3) y = 2﷮5﷯(x − 3) 5y = 2x – 6 2x – 5y − 6 = 0 Since the three point lie on the same Then third point (8, 2) will satisfy the equation of line Putting x = 8, y = 2 in equation 2x − 5y − 6 = 0 2(8) − 5(2) − 6 = 0 16 − 10 − 6 = 0 0 = 0 which is true Hence point (8, 2) lie on line 2x − 5y − 6 = 0 Hence points (8, 2), (3, 0) & ( − 2, − 2) on the same line Hence (3, 0), ( − 2, − 2)& (8, 2) are collinear

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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