# Ex 10.2, 7 - Chapter 10 Class 11 Straight Lines

Last updated at Feb. 3, 2020 by Teachoo

Last updated at Feb. 3, 2020 by Teachoo

Transcript

Ex 10.2, 7 Find the equation of the line which passes through the points (โ1, 1) and (2, โ4). We know that equation of line through two points (x1, y1) & (x2, y2) is ๐ฆ โ ๐ฆ_1 = (๐ฆ_2 โ ๐ฆ_1)/(๐ฅ_2 โ ๐ฅ_1 ) (๐ฅ โ ๐ฅ_1) Since equation of the line through the points (โ1, 1) and (2, โ4). Here, x1 = โ1, y1 = 1 & x2 = 2, y2 = โ4 Putting values (y โ 1) = ( โ4 โ 1)/(2 โ ( โ1)) (x โ (โ1)) (y โ 1) = ( โ5)/(2 + 1) (x + 1) (y โ 1) = ( โ5)/3 (x + 1) 3(y โ 1) = โ5(x + 1) 3y โ 3 = โ5x โ 5 5x + 3y + 2 = 0 Hence, the required equation is 5x + 3y + 2 = 0

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.