Ex 10.2, 2 - Find equation of line (-4, 3) with slope 1/2 . - Ex 10.2

  1. Chapter 10 Class 11 Straight Lines
  2. Serial order wise
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Ex10.2, 2 Find the equation of the line which passes through the point (–4, 3) with slope 1/2 . We know that equation of line passing through point (x0 y0) with slope m is y – y0 = m(x – x0) Given slope (m) = 1/2 & point (x0 , y0) = (–4, 3) Putting values (y – 3) = 1/2 (x – (-4)) (y – 3) = 1/2 (x + 4) 2 (y – 3) = x + 4 2y – 6 = x + 4 2y – x – 6 – 4 = 0 2y – x – 10 = 0 0 = x – 2y + 10 x – 2y + 10 = 0 Which is the required equation

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