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Ex 10.2

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Ex 10.2, 13 You are here

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Last updated at May 29, 2018 by Teachoo

Ex 10.2, 13 Find equation of the line passing through the point (2, 2) and cutting off intercepts on the axes whose sum is 9. Equation of the line in intercept form is / + / = 1 where a = x - intercept & b = y-intercept Given that sum of intercepts is 9 a + b = 9 b = 9 a Putting value b = 9 a in equation / + /(9 ) = 1 Since point A(2, 2) lies on the line, it will satisfy the equation of line Putting x = 2 & y = 2 in the equation 2/ + 2/(9 ) = 1 ((9 a)2 + 2a)/(a(9 a)) = 1 18 2a + 2a = a(9 a) 18 0 = 9a a2 18 = 9a a2 a2 9a + 18 = 0 a2 6a 3a + 18 = 0 a(a 6) 3(a 6)= 0 (a 3) (a 6) = 0 So, a = 3 & a = 6