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Last updated at May 29, 2018 by Teachoo

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Ex 10.2, 13 Find equation of the line passing through the point (2, 2) and cutting off intercepts on the axes whose sum is 9. Equation of the line in intercept form is / + / = 1 where a = x - intercept & b = y-intercept Given that sum of intercepts is 9 a + b = 9 b = 9 a Putting value b = 9 a in equation / + /(9 ) = 1 Since point A(2, 2) lies on the line, it will satisfy the equation of line Putting x = 2 & y = 2 in the equation 2/ + 2/(9 ) = 1 ((9 a)2 + 2a)/(a(9 a)) = 1 18 2a + 2a = a(9 a) 18 0 = 9a a2 18 = 9a a2 a2 9a + 18 = 0 a2 6a 3a + 18 = 0 a(a 6) 3(a 6)= 0 (a 3) (a 6) = 0 So, a = 3 & a = 6

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.