Last updated at May 29, 2018 by Teachoo

Transcript

Ex 10.2, 13 Find equation of the line passing through the point (2, 2) and cutting off intercepts on the axes whose sum is 9. Equation of the line in intercept form is / + / = 1 where a = x - intercept & b = y-intercept Given that sum of intercepts is 9 a + b = 9 b = 9 a Putting value b = 9 a in equation / + /(9 ) = 1 Since point A(2, 2) lies on the line, it will satisfy the equation of line Putting x = 2 & y = 2 in the equation 2/ + 2/(9 ) = 1 ((9 a)2 + 2a)/(a(9 a)) = 1 18 2a + 2a = a(9 a) 18 0 = 9a a2 18 = 9a a2 a2 9a + 18 = 0 a2 6a 3a + 18 = 0 a(a 6) 3(a 6)= 0 (a 3) (a 6) = 0 So, a = 3 & a = 6

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.