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Ex 10.2

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Last updated at Feb. 3, 2020 by Teachoo

Maths Crash Course - Live lectures + all videos + Real time Doubt solving!

Ex 10.2, 16 The length L (in centimetre) of a copper rod is a linear function of its Celsius temperature C. In an experiment, if L = 124.942 when C = 20 and L = 125.134 when C = 110, express L in terms of C. Assuming C is along x-axis & L is along y-axis (x, y) = (C, L) So, we are given two points (20, 124.942) and (110, 125.134) So, from two point form y − y1 =(𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) (x − x1) L − 124.942 = (125.134 − 124.942)/(110 − 20) (C − 20) L − 124.942 = (125.134 − 124.942)/(110 − 20) (C − 20) L − 124.942 = 0.192/90 (C − 20) L = (𝟎.𝟏𝟗𝟐)/𝟗𝟎 (C − 20) + 124.942