Ex 10.2, 12 - Class 11

Transcript

Ex 10.2, 12 Find the equation of a line that cuts off equal intercepts on the coordinate axes and passes through the point (2, 3). Equation of a line by intercept form is x/a + y/b = 1 Where a = x-intercept & b = y-intercept But given that x & y intercept are equal ∴ a = b Thus, equation of line is x/a + y/a = 1 x + y = a x + y – a = 0 Now we need to find value of a Since the line passes through the point (2, 3) ∴ Point (2, 3) will satisfying the equation of line Putting x = 2 & y = 3 in (1) 2 + 3 – a = 0 5 – a = 0 a = 5 Now, Equation of line becomes x + y – a = 0 x + y – 5 = 0 Hence the required equation of line is x + y – 5 = 0