Ex 5.5, 13 - Chapter 5 Class 12 Continuity and Differentiability
Last updated at April 16, 2024 by Teachoo
Logarithmic Differentiation - Type 1
Example 29 Important
Ex 5.5, 3 Important
Ex 5.5, 15
Ex 5.5, 5
Ex 5.5, 1 Important
Ex 5.5, 13 You are here
Ex 5.5, 14 Important
Ex 5.5, 16 Important
Ex 5.5, 17 Important
Ex 5.5, 18
Example 27 Important
Ex 5.5, 2
Misc 22 Important
Misc 3
Misc 7 Important
Example 41
Misc 9 Important
Example 40 (i)
Logarithmic Differentiation - Type 1
Last updated at April 16, 2024 by Teachoo
Ex 5.5, 13 Find 𝑑𝑦/𝑑𝑥 of the functions in, 𝑦^𝑥 = 𝑥^𝑦 Given, 𝑦^𝑥 = 𝑥^𝑦 Taking log both sides log (𝑦^𝑥 ) = log (𝑥^𝑦 ) 𝑥 . log 𝑦=𝑦.log𝑥 Differentiating both sides 𝑤.𝑟.𝑡.𝑥. (𝑑(𝑥 . log 𝑦))/𝑑𝑥 = 𝑑(𝑦.〖 log〗𝑥 )/𝑑𝑥 (As 𝑙𝑜𝑔(𝑎^𝑏 )=𝑏 . 𝑙𝑜𝑔𝑎) Using product Rule As (𝑢𝑣)’ = 𝑢’𝑣 + 𝑣’𝑢 𝑑(𝑥)/𝑑𝑥 . log 𝑦+ 𝑑(log𝑦 )/𝑑𝑥 . 𝑥 =" " 𝑑(𝑦)/𝑑𝑥 " ". log 𝑥 + 𝑑(log𝑥 )/𝑑𝑥 . 𝑦 log 𝑦+𝑥 . 𝑑(log𝑦 )/𝑑𝑥 . 𝑥 = 𝑑𝑦/𝑑𝑥 log 𝑥 + 1/𝑥 . 𝑦 log 𝑦+𝑥 . 𝑑(log𝑦 )/𝑑𝑥 . 𝑑𝑦/𝑑𝑦 = 𝑑𝑦/𝑑𝑥 . log 𝑥 + 𝑦/𝑥 log 𝑦+𝑥 . 𝑑(log𝑦 )/𝑑𝑦 . 𝑑𝑦/𝑑𝑥 = 𝑑𝑦/𝑑𝑥 . log 𝑥 + 𝑦/𝑥 log 𝑦+𝑥 . 1/𝑦 . 𝑑𝑦/𝑑𝑥 = 𝑑𝑦/𝑑𝑥 . log 𝑥 + 𝑦/𝑥 log 𝑦+ 𝑥/𝑦 . 𝑑𝑦/𝑑𝑥 = 𝑑𝑦/𝑑𝑥 . log 𝑥 + 𝑦/𝑥 𝑥/𝑦 . 𝑑𝑦/𝑑𝑥 − 𝑑𝑦/𝑑𝑥 . log 𝑥 = 𝑦/𝑥 − log 𝑦 𝑑𝑦/𝑑𝑥 (𝑥/𝑦 − log 𝑥) = 𝑦/𝑥 − log 𝑦 𝑑𝑦/𝑑𝑥 ((𝑥 − 𝑦 log𝑥)/𝑦) = (𝑦 − 𝑥 log𝑦)/𝑥 𝑑𝑦/𝑑𝑥 = (𝑦 − 𝑥 log𝑦)/𝑥 . 𝑦/(𝑥 − 𝑦 log𝑥 ) 𝒅𝒚/𝒅𝒙 = 𝒚(𝒚 − 𝒙 𝒍𝒐𝒈𝒚 )/𝒙(𝒙 − 𝒚 𝒍𝒐𝒈𝒙 )