Finding derivative of a function by chain rule

Chapter 5 Class 12 Continuity and Differentiability
Concept wise

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### Transcript

Misc 1 Differentiate w.r.t. x the function, (3π₯2 β 9π₯ + 5)^9Let π¦=(3π₯2 β 9π₯ + 5)^9 Differentiating π€.π.π‘.π₯. ππ¦/ππ₯ = (π(3π₯2 β 9π₯ + 5)^9)/ππ₯ = 9(3π₯2 β 9π₯ + 5)^(9 β1) . π(3π₯2 β 9π₯ + 5)/ππ₯ = 9(3π₯2 β 9π₯ + 5)^8 . (π(3π₯2)/ππ₯ β π(9π₯)/ππ₯ β π(5)/ππ₯) = 9(3π₯2 β 9π₯ + 5)^8 . (6π₯β9+0) = 9(3π₯2 β 9π₯ + 5)^8 . (6π₯β9) = 9(3π₯2 β 9π₯ + 5)^8 . 3(2π₯β3) = ππ(πππ β ππ + π)^π (ππβπ)

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#### Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.