Misc 1 - Chapter 5 Class 12 Continuity and Differentiability (Term 1)
Last updated at April 13, 2021 by
Transcript
Misc 1 Differentiate w.r.t. x the function, (3π₯2 β 9π₯ + 5)^9Let π¦=(3π₯2 β 9π₯ + 5)^9 Differentiating π€.π.π‘.π₯. ππ¦/ππ₯ = (π(3π₯2 β 9π₯ + 5)^9)/ππ₯ = 9(3π₯2 β 9π₯ + 5)^(9 β1) . π(3π₯2 β 9π₯ + 5)/ππ₯ = 9(3π₯2 β 9π₯ + 5)^8 . (π(3π₯2)/ππ₯ β π(9π₯)/ππ₯ β π(5)/ππ₯) = 9(3π₯2 β 9π₯ + 5)^8 . (6π₯β9+0) = 9(3π₯2 β 9π₯ + 5)^8 . (6π₯β9) = 9(3π₯2 β 9π₯ + 5)^8 . 3(2π₯β3) = ππ(πππ β ππ + π)^π (ππβπ)
Finding derivative of a function by chain rule
Chapter 5 Class 12 Continuity and Differentiability (Term 1)
Concept wise
- Checking continuity at a given point
- Checking continuity at any point
- Checking continuity using LHL and RHL
- Algebra of continous functions
- Continuity of composite functions
- Checking if funciton is differentiable
-
Finding derivative of a function by chain rule
- Finding derivative of Implicit functions
- Finding derivative of Inverse trigonometric functions
- Finding derivative of Exponential & logarithm functions
- Logarithmic Differentiation - Type 1
- Logarithmic Differentiation - Type 2
- Derivatives in parametric form
- Finding second order derivatives - Normal form
- Finding second order derivatives- Implicit form
- Proofs
- Verify Rolles theorem
- Verify Mean Value Theorem
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.
