Misc 1 - Differentiate (3x2 - 9x + 5)9 - Chapter 5 Class 12

Misc 1 - Chapter 5 Class 12 Continuity and Differentiability - Part 2

  1. Chapter 5 Class 12 Continuity and Differentiability (Term 1)
  2. Concept wise

Transcript

Misc 1 Differentiate w.r.t. x the function, (3π‘₯2 – 9π‘₯ + 5)^9Let 𝑦=(3π‘₯2 – 9π‘₯ + 5)^9 Differentiating 𝑀.π‘Ÿ.𝑑.π‘₯. 𝑑𝑦/𝑑π‘₯ = (𝑑(3π‘₯2 – 9π‘₯ + 5)^9)/𝑑π‘₯ = 9(3π‘₯2 – 9π‘₯ + 5)^(9 βˆ’1) . 𝑑(3π‘₯2 – 9π‘₯ + 5)/𝑑π‘₯ = 9(3π‘₯2 – 9π‘₯ + 5)^8 . (𝑑(3π‘₯2)/𝑑π‘₯ βˆ’ 𝑑(9π‘₯)/𝑑π‘₯ βˆ’ 𝑑(5)/𝑑π‘₯) = 9(3π‘₯2 – 9π‘₯ + 5)^8 . (6π‘₯βˆ’9+0) = 9(3π‘₯2 – 9π‘₯ + 5)^8 . (6π‘₯βˆ’9) = 9(3π‘₯2 – 9π‘₯ + 5)^8 . 3(2π‘₯βˆ’3) = πŸπŸ•(πŸ‘π’™πŸ – πŸ—π’™ + πŸ“)^πŸ– (πŸπ’™βˆ’πŸ‘)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.