Finding derivative of a function by chain rule
Finding derivative of a function by chain rule
Last updated at Aug. 13, 2021 by Teachoo
Ex 5.2, 3 Differentiate the functions with respect to x sinβ‘(ππ₯ + π) Let π¦ = sin (ππ₯ + π) We need to find derivative of π¦, π€.π.π‘.π₯ (ππ¦ )/ππ₯ = (π (sinβ‘γ(ππ₯ + π)γ)" " )/ππ₯ = cos (ππ₯ + π) Γ (π (ππ₯ + π))/ππ₯ = cos (ππ₯ + π)Γ ((π(ππ₯))/ππ₯+ (π(π))/ππ₯) = cos (ππ₯ + π) . (a + 0) = π πππβ‘(ππ + π)