Ex 5.2, 2 - Differentiate cos (sin⁡ x) - Chapter 5 NCERT


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Ex 5.2, 2 Differentiate the functions with respect to π‘₯ cos (sin⁑π‘₯) Let 𝑦 = cos (sin⁑π‘₯) We need to find derivative of 𝑦, 𝑀.π‘Ÿ.𝑑.π‘₯ i.e. (𝑑𝑦 )/𝑑π‘₯ = (𝑑(cos (sin⁑π‘₯ )))/𝑑π‘₯ = βˆ’ sin⁑(sin⁑π‘₯) . (𝑑(sin⁑〖π‘₯)γ€—)/𝑑π‘₯ = βˆ’ sin⁑(sin⁑π‘₯) . cos⁑π‘₯ = βˆ’ πœπ¨π¬β‘π’™ π’”π’Šπ’ ⁑(𝐬𝐒𝐧⁑〖𝒙)γ€—

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.