Finding derivative of a function by chain rule
Finding derivative of a function by chain rule
Last updated at April 13, 2021 by Teachoo
Ex 5.2, 4 Differentiate the functions with respect to x sec (tan ( βπ₯ )) Let π¦ = sec (tan βπ₯ ) We need to find Derivative of π¦ i.e. π¦β = (secβ‘γγ(tanγβ‘βπ₯)γ )^β² = γπ¬ππ γβ‘γ(πππ§β‘βπ)γ γπππ§ γβ‘γ(πππβ‘βπ)γ (tanβ‘βπ₯ )^β² = γsec γβ‘γ(tanβ‘βπ₯)γ γtan γβ‘γ(tanβ‘βπ₯)γ. ("sec2 " βπ₯ " . " (βπ₯)^β²) = γsec γβ‘γ(tanβ‘βπ₯)γ γtan γβ‘γ(tanβ‘βπ₯)γ. sec2 " " βπ₯ Γ 1/(2βπ₯) = (πππβ‘γ(πππβ‘βπ γ)πππβ‘γ(πππβ‘βπ γ)γπππγ^πβ‘βπ )/(πβπ)