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Transcript

Example 31 Find 𝑑𝑦/𝑑π‘₯ , if π‘₯ = π‘Ž cosβ‘πœƒ, 𝑦 = π‘Ž sin ΞΈ.Here 𝑑𝑦/𝑑π‘₯ = (𝑑𝑦/π‘‘πœƒ)/(𝑑π‘₯/π‘‘πœƒ) Calculating π’…π’š/π’…πœ½ 𝑦 = π‘Ž sin ΞΈ 𝑑𝑦/π‘‘πœƒ = 𝑑(π‘Ž sin πœƒ)/π‘‘πœƒ 𝑑𝑦/π‘‘πœƒ = 𝒂 π’„π’π’”β‘πœ½ Calculating 𝒅𝒙/π’…πœ½ 𝑦 = π‘Ž cos ΞΈ 𝑑𝑦/π‘‘πœƒ = 𝑑(π‘Ž cos πœƒ)/π‘‘πœƒ 𝑑𝑦/π‘‘πœƒ = βˆ’π’‚ π’”π’Šπ’β‘πœ½ Now, 𝑑𝑦/𝑑π‘₯ = (𝑑𝑦/π‘‘πœƒ)/(𝑑π‘₯/π‘‘πœƒ) 𝑑𝑦/𝑑π‘₯ = (π‘Ž cos⁑θ)/(βˆ’π‘Ž sin⁑θ ) π’…π’š/𝒅𝒙 = βˆ’πœπ¨π­β‘π›‰

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.