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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Ex 5.6, 1 If x and y are connected parametrically by the equations without eliminating the parameter, Find 𝑑𝑦/𝑑π‘₯, x = 2γ€–π‘Žπ‘‘γ€—^2, y = γ€–π‘Žπ‘‘γ€—^4Here 𝑑𝑦/𝑑π‘₯ = (𝑑𝑦/𝑑𝑑)/(𝑑π‘₯/𝑑𝑑) Calculating π’…π’š/𝒅𝒕 𝑦 = γ€–π‘Žπ‘‘γ€—^4 𝑑𝑦/𝑑𝑑 " =" γ€–4π‘Žπ‘‘γ€—^(4 βˆ’1) "=" γ€–4π‘Žπ‘‘γ€—^3 Calculating 𝒅𝒙/𝒅𝒕 π‘₯ = 2γ€–π‘Žπ‘‘γ€—^2 𝑑π‘₯/𝑑𝑑 " =" 2 Γ— 2π‘Žπ‘‘ "=" 4π‘Žπ‘‘ Now, 𝑑𝑦/𝑑π‘₯ = (𝑑𝑦/𝑑𝑑)/(𝑑π‘₯/𝑑𝑑) Putting values 𝑑𝑦/𝑑π‘₯ = (4π‘Žπ‘‘^3)/4π‘Žπ‘‘ π’…π’š/𝒅𝒙 = t2

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.