Check Full Chapter Explained - Continuity and Differentiability - Continuity and Differentiability Class 12



  1. Chapter 5 Class 12 Continuity and Differentiability
  2. Concept wise


Misc 8 Differentiate 𝑀.π‘Ÿ.𝑑. π‘₯ the function, cos ⁑(π‘Ž cos⁑π‘₯+𝑏 sin⁑π‘₯), for some constant π‘Ž and 𝑏. Let 𝑦 = cos ⁑(π‘Ž cos⁑π‘₯+𝑏 sin⁑π‘₯) Differentiating 𝑀.π‘Ÿ.𝑑.π‘₯. 𝑑𝑦/𝑑π‘₯ = (𝑑(cos((a cos⁑x+b sin⁑x )))/𝑑π‘₯ 𝑑𝑦/𝑑π‘₯ = βˆ’sin⁑π‘₯ (π‘Ž cos⁑π‘₯+𝑏 sin⁑π‘₯) . (𝑑⁑(π‘Ž cos⁑π‘₯+𝑏 sin⁑π‘₯))/𝑑π‘₯ = βˆ’sin⁑π‘₯ (π‘Ž cos⁑π‘₯+𝑏 sin⁑π‘₯) . (π‘Ž .𝑑⁑(cos⁑π‘₯ )/𝑑π‘₯+𝑏 .𝑑⁑(sin⁑π‘₯ )/𝑑π‘₯) = βˆ’sin⁑π‘₯ (π‘Ž cos⁑π‘₯+𝑏 sin⁑π‘₯) . (π‘Ž(βˆ’sin⁑π‘₯ )+𝑏 (cos⁑π‘₯ )) = βˆ’sin⁑π‘₯ (π‘Ž cos⁑π‘₯+𝑏 sin⁑π‘₯) . (βˆ’π‘Ž sin⁑π‘₯+𝑏 cos⁑π‘₯ ) = βˆ’sin⁑π‘₯ (π‘Ž cos⁑π‘₯+𝑏 sin⁑π‘₯) . βˆ’(π‘Ž sin⁑π‘₯βˆ’π‘ cos⁑π‘₯ ) = 𝐬𝐒𝐧⁑〖 (𝒂 𝒄𝒐𝒔⁑𝒙+𝒃 π’”π’Šπ’β‘π’™)" " (𝒂 π’”π’Šπ’β‘π’™βˆ’π’ƒ 𝒄𝒐𝒔⁑𝒙 )γ€—

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.