Ex 11.2, 13 - Chapter 11 Class 12 Three Dimensional Geometry (Term 2)
Last updated at May 29, 2018 by Teachoo
Ex 11.2
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Ex 11.2, 10 (i) Important Deleted for CBSE Board 2022 Exams
Ex 11.2, 10 (ii)
Ex 11.2, 11 (i) Important Deleted for CBSE Board 2022 Exams
Ex 11.2, 11 (ii)
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Ex 11.2, 13 You are here
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Chapter 11 Class 12 Three Dimensional Geometry (Term 2)
Serial order wise
Transcript
Ex 11.2, 13 Show that the lines 5 7 = + 2 5 = 1 and 1 = 2 = 3 are perpendicular to each other. Two lines 1 1 = 1 1 = 1 1 and 2 2 = 2 2 = 2 2 are perpendicular to each other if + + = 0 So, 1 2 + 1 2 + 1 2 = (7 1) + ( 5 2) + (1 3) = 7 + ( 10) + 3 = 0 Therefore, the two given lines are perpendicular to each other.
