Ex 11.2, 4 - Find equation of line passes (1, 2, 3), parallel - Ex 11.2

  1. Chapter 11 Class 12 Three Dimensional Geometry
  2. Serial order wise
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Ex 11.2, 4 Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3 ๐‘–๏ทฏ + 2 ๐‘—๏ทฏ โ€“ 2 ๐‘˜๏ทฏ . Equation of a line passing through a point with position vector ๐‘Ž๏ทฏ , and parallel to a vector ๐‘๏ทฏ is ๐‘Ÿ๏ทฏ = ๐‘Ž๏ทฏ + ๐œ† ๐‘๏ทฏ Since line passes through (1, 2, 3) ๐‘Ž๏ทฏ = 1 ๐‘–๏ทฏ + 2 ๐‘—๏ทฏ + 3 ๐‘˜๏ทฏ Since line is parallel to 3 ๐‘–๏ทฏ + 2 ๐‘—๏ทฏ โˆ’ 2 ๐‘˜๏ทฏ ๐‘๏ทฏ = 3 ๐‘–๏ทฏ + 2 ๐‘—๏ทฏ โˆ’ 2 ๐‘˜๏ทฏ Equation of line ๐‘Ÿ๏ทฏ = ๐‘Ž๏ทฏ + ๐œ† ๐‘๏ทฏ ๐’“๏ทฏ = ( ๐’Š๏ทฏ + 2 ๐’‹๏ทฏ + 3 ๐’Œ๏ทฏ) + ๐œ† (3 ๐’Š๏ทฏ + 2 ๐’‹๏ทฏ โˆ’ 2 ๐’Œ๏ทฏ)

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