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Ex 11.2, 4 - Chapter 11 Class 12 Three Dimensional Geometry
Last updated at Aug. 14, 2023 by Teachoo
Ex 11.2
Ex 11.2, 1
Ex 11.2, 2
Ex 11.2, 3 Important
Ex 11.2, 4 You are here
Ex 11.2, 5 Important
Ex 11.2, 6
Ex 11.2, 7 Important
Ex 11.2, 8 (i) Important
Ex 11.2, 8 (ii)
Ex 11.2, 9 (i) Important
Ex 11.2, 9 (ii)
Ex 11.2, 10 Important
Ex 11.2, 11
Ex 11.2, 12 Important
Ex 11.2, 13 Important
Ex 11.2, 14
Ex 11.2, 15 Important
Question 1 Important Deleted for CBSE Board 2024 Exams
Question 2 Deleted for CBSE Board 2024 Exams
Chapter 11 Class 12 Three Dimensional Geometry
Serial order wise
Transcript
Ex 11.2, 4 Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3𝑖 ̂ + 2𝑗 ̂ – 2𝑘 ̂ . Equation of a line passing through a point with position vector 𝑎 ⃗, and parallel to a vector 𝑏 ⃗ is 𝒓 ⃗ = 𝒂 ⃗ + 𝜆𝒃 ⃗ Since line passes through (1, 2, 3) 𝒂 ⃗ = 1𝒊 ̂ + 2𝒋 ̂ + 3𝒌 ̂ Since line is parallel to 3𝑖 ̂ + 2𝑗 ̂ − 2𝑘 ̂ 𝒃 ⃗ = 3𝒊 ̂ + 2𝒋 ̂ − 2𝒌 ̂ Equation of line 𝑟 ⃗ = 𝑎 ⃗ + 𝜆𝑏 ⃗ 𝒓 ⃗ = (𝒊 ̂ + 2𝒋 ̂ + 3𝒌 ̂) + 𝜆 (3𝒊 ̂ + 2𝒋 ̂ − 2𝒌 ̂)
