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Last updated at Dec. 8, 2016 by Teachoo

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Ex 11.2, 4 Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3 ๐๏ทฏ + 2 ๐๏ทฏ โ 2 ๐๏ทฏ . Equation of a line passing through a point with position vector ๐๏ทฏ , and parallel to a vector ๐๏ทฏ is ๐๏ทฏ = ๐๏ทฏ + ๐ ๐๏ทฏ Since line passes through (1, 2, 3) ๐๏ทฏ = 1 ๐๏ทฏ + 2 ๐๏ทฏ + 3 ๐๏ทฏ Since line is parallel to 3 ๐๏ทฏ + 2 ๐๏ทฏ โ 2 ๐๏ทฏ ๐๏ทฏ = 3 ๐๏ทฏ + 2 ๐๏ทฏ โ 2 ๐๏ทฏ Equation of line ๐๏ทฏ = ๐๏ทฏ + ๐ ๐๏ทฏ ๐๏ทฏ = ( ๐๏ทฏ + 2 ๐๏ทฏ + 3 ๐๏ทฏ) + ๐ (3 ๐๏ทฏ + 2 ๐๏ทฏ โ 2 ๐๏ทฏ)

Ex 11.2

Ex 11.2, 1

Ex 11.2, 2

Ex 11.2, 3 Important

Ex 11.2, 4 You are here

Ex 11.2, 5 Important

Ex 11.2, 6

Ex 11.2, 7 Important

Ex 11.2, 8

Ex 11.2, 9 Important

Ex 11.2, 10 Important

Ex 11.2, 11 Important

Ex 11.2, 12 Important

Ex 11.2, 13

Ex 11.2, 14 Important

Ex 11.2, 15 Important

Ex 11.2, 16 Important

Ex 11.2, 17 Important

Chapter 11 Class 12 Three Dimensional Geometry

Serial order wise

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.