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Ex 11.2

Ex 11.2, 1

Ex 11.2, 2

Ex 11.2, 3 Important

Ex 11.2, 4 You are here

Ex 11.2, 5 Important

Ex 11.2, 6

Ex 11.2, 7 Important

Ex 11.2, 8

Ex 11.2, 9 Important

Ex 11.2, 10 (i) Important Deleted for CBSE Board 2022 Exams

Ex 11.2, 10 (ii)

Ex 11.2, 11 (i) Important Deleted for CBSE Board 2022 Exams

Ex 11.2, 11 (ii)

Ex 11.2, 12 Important

Ex 11.2, 13

Ex 11.2, 14 Important

Ex 11.2, 15 Important

Ex 11.2, 16

Ex 11.2, 17 Important

Chapter 11 Class 12 Three Dimensional Geometry (Term 2)

Serial order wise

Last updated at Dec. 8, 2016 by Teachoo

Ex 11.2, 4 Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3 𝑖 + 2 𝑗 – 2 𝑘 . Equation of a line passing through a point with position vector 𝑎 , and parallel to a vector 𝑏 is 𝑟 = 𝑎 + 𝜆 𝑏 Since line passes through (1, 2, 3) 𝑎 = 1 𝑖 + 2 𝑗 + 3 𝑘 Since line is parallel to 3 𝑖 + 2 𝑗 − 2 𝑘 𝑏 = 3 𝑖 + 2 𝑗 − 2 𝑘 Equation of line 𝑟 = 𝑎 + 𝜆 𝑏 𝒓 = ( 𝒊 + 2 𝒋 + 3 𝒌) + 𝜆 (3 𝒊 + 2 𝒋 − 2 𝒌)