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Ex 11.2

Ex 11.2, 1

Ex 11.2, 2

Ex 11.2, 3 Important

Ex 11.2, 4 You are here

Ex 11.2, 5 Important

Ex 11.2, 6

Ex 11.2, 7 Important

Ex 11.2, 8 (i) Important

Ex 11.2, 8 (ii)

Ex 11.2, 9 (i) Important

Ex 11.2, 9 (ii)

Ex 11.2, 10 Important

Ex 11.2, 11

Ex 11.2, 12 Important

Ex 11.2, 13 Important

Ex 11.2, 14

Ex 11.2, 15 Important

Question 1 Important Deleted for CBSE Board 2024 Exams

Question 2 Deleted for CBSE Board 2024 Exams

Chapter 11 Class 12 Three Dimensional Geometry

Serial order wise

Last updated at May 29, 2023 by Teachoo

Ex 11.2, 4 Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3 𝑖 + 2 𝑗 – 2 𝑘 . Equation of a line passing through a point with position vector 𝑎 , and parallel to a vector 𝑏 is 𝑟 = 𝑎 + 𝜆 𝑏 Since line passes through (1, 2, 3) 𝑎 = 1 𝑖 + 2 𝑗 + 3 𝑘 Since line is parallel to 3 𝑖 + 2 𝑗 − 2 𝑘 𝑏 = 3 𝑖 + 2 𝑗 − 2 𝑘 Equation of line 𝑟 = 𝑎 + 𝜆 𝑏 𝒓 = ( 𝒊 + 2 𝒋 + 3 𝒌) + 𝜆 (3 𝒊 + 2 𝒋 − 2 𝒌)