Last updated at Dec. 8, 2016 by Teachoo

Transcript

Ex 11.2, 4 Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3 ๐๏ทฏ + 2 ๐๏ทฏ โ 2 ๐๏ทฏ . Equation of a line passing through a point with position vector ๐๏ทฏ , and parallel to a vector ๐๏ทฏ is ๐๏ทฏ = ๐๏ทฏ + ๐ ๐๏ทฏ Since line passes through (1, 2, 3) ๐๏ทฏ = 1 ๐๏ทฏ + 2 ๐๏ทฏ + 3 ๐๏ทฏ Since line is parallel to 3 ๐๏ทฏ + 2 ๐๏ทฏ โ 2 ๐๏ทฏ ๐๏ทฏ = 3 ๐๏ทฏ + 2 ๐๏ทฏ โ 2 ๐๏ทฏ Equation of line ๐๏ทฏ = ๐๏ทฏ + ๐ ๐๏ทฏ ๐๏ทฏ = ( ๐๏ทฏ + 2 ๐๏ทฏ + 3 ๐๏ทฏ) + ๐ (3 ๐๏ทฏ + 2 ๐๏ทฏ โ 2 ๐๏ทฏ)

Chapter 11 Class 12 Three Dimensional Geometry

Serial order wise

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.