Ex 11.2, 12 - Chapter 11 Class 12 Three Dimensional Geometry
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 11.2, 12 Find the values of so that the lines 1 3 = 7 14 2 = 3 2 and 7 7 3 = 5 1 = 6 5 are at right angles. Two lines 1 1 = 1 1 = 1 1 and 2 2 = 2 2 = 2 2 are at right angles to each other if + + = 0 Since the lines are perpendicular 1 2+ 1 2+ 1 2 = 0 3 3 7 + 2 7 1 + (2 5) = 0 9 7 + 2 7 10 = 0 11 7 = 10 p = 10 7 11 p =
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Chapter 11 Class 12 Three Dimensional Geometry
Serial order wise
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