Ex 11.2

Ex 11.2, 1

Ex 11.2, 2

Ex 11.2, 3 Important

Ex 11.2, 4

Ex 11.2, 5 Important

Ex 11.2, 6

Ex 11.2, 7 Important You are here

Ex 11.2, 8

Ex 11.2, 9 Important

Ex 11.2, 10 (i) Important Deleted for CBSE Board 2022 Exams

Ex 11.2, 10 (ii)

Ex 11.2, 11 (i) Important Deleted for CBSE Board 2022 Exams

Ex 11.2, 11 (ii)

Ex 11.2, 12 Important

Ex 11.2, 13

Ex 11.2, 14 Important

Ex 11.2, 15 Important

Ex 11.2, 16

Ex 11.2, 17 Important

Chapter 11 Class 12 Three Dimensional Geometry (Term 2)

Serial order wise

Last updated at Feb. 1, 2020 by Teachoo

Ex 11.2, 7 The Cartesian equation of a line is (𝑥 − 5)/3 = (𝑦 + 4)/7 = (𝑧 − 6)/2. Write its vector form.Cartesian equation : (𝑥 − 5)/3 = (𝑦 + 4)/7 = (𝑧 − 6)/2 (𝑥 − 5)/3 = (𝑦 − (−4))/7 = (𝑧 − 6)/2 Equation of a line in Cartesian form is given by (𝑥 − 𝑥1)/𝑎 = (𝑦 − 𝑦1)/𝑏 = (𝑧 − 𝑧1)/𝑐 Comparing (1) and (2), 𝑥1 = 5, 𝑦1 = −4, 𝑧1 = 6 𝑎 = 3, b = 7, c = 2 Cartesian equation : (𝑥 − 5)/3 = (𝑦 + 4)/7 = (𝑧 − 6)/2 (𝑥 − 5)/3 = (𝑦 − (−4))/7 = (𝑧 − 6)/2 Equation of a line in Cartesian form is given by (𝑥 − 𝑥1)/𝑎 = (𝑦 − 𝑦1)/𝑏 = (𝑧 − 𝑧1)/𝑐 Comparing (1) and (2), 𝑥1 = 5, 𝑦1 = −4, 𝑧1 = 6 𝑎 = 3, b = 7, c = 2 Equation of line in vector form is 𝑟 ⃗ = 𝑎 ⃗ + 𝜆𝑏 ⃗ Where 𝑎 ⃗ = 𝑥1𝑖 ̂ + y1𝑗 ̂ + z1𝑘 ̂ = 5𝑖 ̂ − 4𝑗 ̂ + 6𝑘 ̂ & 𝑏 ⃗ = 𝑎𝑖 ̂ + b𝑗 ̂ + c𝑘 ̂ = 3𝑖 ̂ + 7𝑗 ̂ + 2𝑘 ̂ Now, 𝑟 ⃗ = (5𝒊 ̂ − 4𝒋 ̂ + 6𝒌 ̂) + 𝜆 (3𝒊 ̂ + 7𝒋 ̂ + 2𝒌 ̂)