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Ex 11.2, 6 - Cartesian equation of line (-2, 4, -5), parallel to - Equation of line  - given point and //vector

Ex 11.2, 6 - Chapter 11 Class 12 Three Dimensional Geometry - Part 2

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Ex 11.2, 6 Find the Cartesian equation of the line which passes through the point ( 2, 4, 5) and parallel to the line given by + 3 3 = 4 5 = + 8 6 . Equation of a line passing through (x1, y1, z1) and parallel to a line having direction ratios a, b, c is 1 = 1 = 1 Since the line passes through ( 2, 4, 5) 1 = 2, y1 = 4 , z1 = 5 Since the line is parallel to + 3 3 = 4 5 = + 8 6 = 3, b = 5 c = 6 Therefore, equation of line in Cartesian form is ( 2) 3 = 4 5 = ( 5) 6 + = = +

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.