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Last updated at Feb. 1, 2020 by Teachoo

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Misc 19 If ΞΈ is the angle between any two vectors π β and π β, then |π β" β " π β | = |π β" Γ " π β | when ΞΈ is equal to (A) 0 (B) π/4 (C) π/2 (D) Ο π β" β " π β = |π β ||π β | cosβ‘"ΞΈ" |π β" β " π β | = ||π β ||π β |cosβ‘"ΞΈ" | = |π β ||π β | cosβ‘"ΞΈ" (π βΓπ β ) = |π β ||π β | π ππβ‘"ΞΈ" π Μ |π βΓπ β |= ||π β ||π β |sinβ‘γ"ΞΈ " π Μ γ | = |π β ||π β |π ππ ΞΈ |π Μ | = |π β ||π β |π ππ ΞΈ Given, |π β" β " π β | = |π βΓπ β | So, |π β ||π β | cos ΞΈ = |π β ||π β | sin ΞΈ cos ΞΈ = sin ΞΈ We know that cos π/4 = sin π/4 = 1/β2 β΄ ΞΈ = π /π Therefore, the angle between the vectors π β and π β is π/4, So, option (B) is correct.

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.