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Last updated at May 6, 2021 by Teachoo

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Misc 5 Find the value of x for which x(๐ ฬ + ๐ ฬ + ๐ ฬ) is a unit vector.Let ๐ โ = x(๐ ฬ + ๐ ฬ + ๐ ฬ) So, ๐ โ = ๐ฅ๐ ฬ + ๐ฅ๐ ฬ + ๐ฅ๐ ฬ Given, ๐ โ is a unit vector Magnitude of ๐ โ is 1. So, |๐ โ | = 1 Thus, Magnitude of ๐ โ = 1 โ(๐ฅ^2+๐ฅ2+๐ฅ2) = 1 โ3๐ฅ2 = 1 ยฑโ3 ๐ฅ = 1 ๐ = ยฑ๐/โ๐ Note We take ยฑ because x can have both positive and negative value

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Misc 6

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Misc 9

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Misc 16 (MCQ) Important

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.