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Last updated at Feb. 1, 2020 by Teachoo
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Misc 5 Find the value of x for which x(๐ ฬ + ๐ ฬ + ๐ ฬ) is a unit vector.Let ๐ โ = x(๐ ฬ + ๐ ฬ + ๐ ฬ) So, ๐ โ = ๐ฅ๐ ฬ + ๐ฅ๐ ฬ + ๐ฅ๐ ฬ Given, ๐ โ is a unit vector Magnitude of ๐ โ is 1. So, |๐ โ | = 1 Magnitude of ๐ โ = โ(๐ฅ^2+๐ฅ2+๐ฅ2) |๐ โ | = โ3๐ฅ2 |๐ โ | = ยฑโ3 ๐ฅ Note We take ยฑ because x can have both positive and negative value Now, |๐ โ | = 1 ยฑโ3 ๐ฅ = 1 ๐ = ยฑ๐/โ๐
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