Misc 5 - Chapter 10 Class 12 Vector Algebra
Last updated at Dec. 24, 2019 by Teachoo
Transcript
Misc 5 Find the value of x for which x(π Μ + π Μ + π Μ) is a unit vector. Let π β = x(π Μ + π Μ + π Μ) So, π β = π₯π Μ + π₯π Μ + π₯π Μ Given, π β is a unit vector Magnitude of π β is 1. So, |π β | = 1 Magnitude of π β = β(π₯2+π₯2+π₯2) |π β | = β3π₯2 = Β±β3 π₯ Now, |π β | = 1 Β±β3 π₯ = 1 π = Β±π/βπ Note: We take Β± because x can have both positive and negative value
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.