Last updated at Dec. 24, 2019 by Teachoo

Transcript

Misc 6 Find a vector of magnitude 5 units, and parallel to the resultant of the vectors π β = 2π Μ + 3π Μ β π Μ and π β = π Μ β 2π Μ + π Μ. π β = 2π Μ + 3π Μ β π Μ π β = π Μ β 2π Μ + π Μ (π β + π β) = (2 + 1)π Μ + (3 β 2)π Μ + (β1 + 1)π Μ = 3π Μ + 1π Μ + 0π Μ Let π β = (π β + π β) β΄ π β = 3π Μ + 1π Μ + 0π Μ Magnitude of π β = β(32+12+02) |π β | = β(9+1) = β10 Unit vector in direction of π β = 1/|π β | Γ π β π Μ = 1/β10 Γ [3π Μ+1π Μ+0π Μ ] π Μ = π/βππ π Μ + π/βππ π Μ + 0π Μ Vector with magnitude 1 = 3/β10 π Μ + 1/β10 π Μ + 0π Μ Vector with magnitude 5 = 5 Γ [3/β10 " " π Μ" + " 1/β10 π Μ" + 0" π Μ ] = 15/β10 π Μ + 2/β10 π Μ + 0π Μ = 15/β10 π Μ + 2/β10 π Μ Rationalizing = 15/β10 Γ β10/β10 π Μ + 2/β10 "Γ " β10/β10 π Μ = (15β10)/10 π Μ + (2β10)/10 π Μ = (3β10)/2 π Μ + β10/5 π Μ Hence the required vector is (πβππ)/π π Μ + βππ/π π Μ

Miscellaneous

Misc 1
Important

Misc 2

Misc 3 Important

Misc 4

Misc 5 Important

Misc 6 You are here

Misc 7 Important

Misc 8 Important

Misc 9

Misc 10 Important

Misc 11 Important

Misc 12 Important

Misc 13 Important

Misc 14 Important

Misc 15 Important

Misc 16 Important

Misc 17 Important

Misc 18 Important

Misc 19 Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.