Misc 6 - Chapter 10 Class 12 Vector Algebra

Transcript

Misc 6 Find a vector of magnitude 5 units, and parallel to the resultant of the vectors = 2 + 3 and = 2 + . = 2 + 3 = 2 + ( + ) = (2 + 1) + (3 2) + ( 1 + 1) = 3 + 1 + 0 Let = ( + ) = 3 + 1 + 0 Magnitude of = 32+12+02 = 9+1 = 10 Unit vector in direction of = 1 = 1 10 3 +1 +0 = + + 0 Vector with magnitude 1 = 3 10 + 1 10 + 0 Vector with magnitude 5 = 5 3 10 + 1 10 + 0 = 15 10 + 2 10 + 0 . = 15 10 + 2 10 . Hence the required vector is + .