Question 14 - CBSE Class 10 Sample Paper for 2027 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at October 9, 2026 by Teachoo

Question 14 — slide 36

Question 14 — slide 37

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Question 14 PM is a median of △PQR with vertices P(5,−6),Q(6,4) and R(0,0). The length of PM is: (A) 2sqrt(17) units (B) 2sqrt(15) units (C) sqrt(101) units (D) 10 unit Joining vertex P to line QR such that PM is the median Coordinates of M = Coordinates of Mid point of QR = ((6 + 0)/(2),(4 + 0)/(2)) =((6 )/(2),(4)/(2)) Q (6, 4) R (0, 0) P (5, –6) M = (3, 2) Finding length of PM Length of PM = sqrt((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2) = sqrt((3−5)2+(2−(−6))2) = sqrt((−2)2+82) = sqrt(4+64) = sqrt(𝟔𝟖) = sqrt(4 × 17) = sqrt(4) × sqrt(17) = 𝟐sqrt(𝟏𝟕) units So, the correct answer is (A) (3, 2) Q (6, 4) R (0, 0) P (5, –6) M

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